The simply supported beam is subjected to the force F =690 N and the uniform distributed load with intensity w = 200 N/m. Draw the shear force and bending moment diagrams (in your homework documentation) and determine the equations for V(x) and M(x). Take x = 0 at point A. ру W a B b. F Vc 2013 Michael Swanbom D c- → BY NC SA

Structural Analysis
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Author:KASSIMALI, Aslam.
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Chapter2: Loads On Structures
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The simply supported beam is subjected to the force F =690
N and the uniform distributed load with intensity w = 200
N/m. Draw the shear force and bending moment diagrams (in
your homework documentation) and determine the equations
for V(x) and M(x). Take x = 0 at point A.
ру
Variable Value
a
b
W
Values for dimensions on the figure are given in the following
table. Note the figure may not be to scale.
с
5.80 m
3.19 m
3.77 m
Support Reactions
The reaction at A is
The reaction at Dis
In section BC:
V(x)=
+
B
In section CD:
V(x)=
Shear Force and Bending Moment Equations
In section AB:
V(x)=
N-m.
N-m.
N.
N-m.
2013 Michael Swanbom
Ⓒ030
N.
N and M(x)=
N and M(x)=
N and M(x)=
Transcribed Image Text:The simply supported beam is subjected to the force F =690 N and the uniform distributed load with intensity w = 200 N/m. Draw the shear force and bending moment diagrams (in your homework documentation) and determine the equations for V(x) and M(x). Take x = 0 at point A. ру Variable Value a b W Values for dimensions on the figure are given in the following table. Note the figure may not be to scale. с 5.80 m 3.19 m 3.77 m Support Reactions The reaction at A is The reaction at Dis In section BC: V(x)= + B In section CD: V(x)= Shear Force and Bending Moment Equations In section AB: V(x)= N-m. N-m. N. N-m. 2013 Michael Swanbom Ⓒ030 N. N and M(x)= N and M(x)= N and M(x)=
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