The significance level and P-value of a hypothesis test are given. Decide whether the null hypothesis should be rejected. a = 0.01, P-value = 0.003 OA) Reject the null hypothesis. OB) Do not reject the null hypothesis.
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- The P-value for a hypothesis test is shown. Use the P-value to decide whether to reject Ho when the level of significance is (a) a = 0.01, (b) a = 0.05, and (c) a = 0.10. P= 0.0961 (a) Do you reject or fail to reject Ho at the 0.01 level of significance? O A. Reject Ho because the P-value, 0.0961, is greater than a =0.01. O B. Fail to reject Ho because the P-value, 0.0961, is greater than a = 0.01. O C. Reject Ho because the P-value, 0.0961, is less than a = 0.01. O D. Fail to reject Ho because the P-value, 0.0961, is less than a = 0.01. (b) Do you reject or fail to reject Ho at the 0.05 level of significance? O A. Fail to reject Ho because the P-value, 0.0961, is less than a = 0.05. O B. Fail to reject Ho because the P-value, 0.0961, is greater than a = 0.05. O C. Reject Ho because the P-value, 0.0961, is less than a = 0.05. O D. Reject Ho because the P-value, 0.0961, is greater than a = 0.05. (c) Do you reject or fail to reject Ho at the 0.10 level of significance? O A. Fail to…The P-value for a hypothesis test is shown. Use the P-value to decide whether to reject Ho when the level of significance is (a) a = 0.01, (b) a =0.05, and (c) a= 0.10. P= 0.1089 (a) Do you reject or fail to reject Ho at the 0.01 level of significance? O A. Reject Ho because the P-value, 0.1089, is greater than a= 0.01. O B. Reject H, because the P-value, 0.1089, is less than a= 0.01. O C. Fail to reject Ho because the P-value, 0.1089, is less than a = 0.01. D. Fail to reject Ho because the P-value, 0.1089, is greater than a = 0.01. (b) Do you reject or fail to reject Ho at the 0.05 level of significance? O A. Fail to reject Ho because the P-value, 0.1089, is greater than a = 0.05. 0.05. O B. Reject H, because the P-value, 0.1089, is greater than O C. Fail to reject Ho because the P-value, 0.1089, is less than a = 0.05. O D. Reject H, because the P-value, 0.1089, is less than a = 0.05.Identify the type I error and the type II error for a hypothesis test of the indicated claim. The percentage of college students who own cars is less than 35%. Identify the type I error. Choose the correct answer below. O A. Reject the null hypothesis that the percentage of college students who own cars is less than 35% when it is actually true. 2 OB. Fail to reject the null hypothesis that the percentage of college students who own cars is greater than or equal to 35% when it is actually false. OC. Reject the null hypothesis that the percentage of college students who own cars is greater than or equal to 35% when it is actually true. O D. Fail to reject the null hypothesis that the percentage of college students who own cars is less than 35% when it is actually false. Identify the type II erfor. Choose the correct answer below... O A. Fail to reject the null hypothesis that the percentage of college students who own cars is greater than or equal to 35% when it is actually false. OB.…
- Use technology to find the P-value for the hypothesis test described below. The claim is that for a smartphone carrier's data speeds at airports, the mean is μ=16.00 Mbps. The sample size is n=26 and the test statistic is t =1.554 A.) P-Value=Use technology to find the P-value for the hypothesis test described below. The claim is that for 12 AM body temperatures, the mean is μ > 98.6 °F. The sample size is n = 3 and the test statistic is t = 1.234.A null and alternative hypothesis are given. Determine whether the hypothesis test is left-tailed, right-tailed, or two-tailed. Ho Ś 4.8 Ha > 4.8 What type of test is being conducted in this problem? O A. Two-tailed test O B. Right-tailed test O C. Left-tailed test
- Test the hypothesis using the P-value approach. Be sure to verify the requirements of the test. H0: p=0.77 versus H1: p≠0.77 n=500, x=380, a=0.1A researcher wanted to determine if carpeted rooms contain more bacteria than uncarpeted rooms. The table shows the results for the number of bacteria per cubic foot for both types of rooms. Full data set O Carpeted Uncarpeted 9.4 9.1 16 10.8 6.4 10.8 14.8 8.8 11.5 11.6 13.7 9.4 10.7 12.4 13.4 7.8 Determine whether carpeted rooms have more bacteria than uncarpeted rooms at the a = 0.05 level of significance. Normal probability plots indicate that the data are approximately normal and boxplots indicate that there are no outliers. State the null and alternative hypotheses. Let population 1 be carpeted rooms and population 2 be uncarpeted rooms. OA Ho P1 H2 B. Ho H1 F2 OC Ho H= H2The Pavalue for a hypothesis test is shown. Use the P-value to decide whether to reject Ho when the level of significance is (a) a = 0.01, (b) a = 0.05. and (c)g=0 10 P=0.0816 (a) Do you reject or fail to reject Ho at the 0.01 level of significance? O A. Fail to reject Ho because the P-value, 0.0816, is less than a = 0.01. O B. Fail to reject H, because the P-value, 0.0816, is greater than a= 0.01. OC. Reject H, because the P-value, 0.0816, is less than a=0.01. O D. Reject Ho because the P-value, 0.0816, is greater thana= 0.01. (b) Do you reject or fail to reject H, at the 0.05 level of significance? O A. Reject Ho because the P-value, 0.0816, is less than a =0.05. O B. Fail to reject H, because the P-value, 0.0816, is greater than a= 0.05. OC. Reject H, because the P-value, 0.0816, is greater than oa 0.05. O D. Fail to reject Ho because the P-value, 0.0816, is less than a = 0,05. (c) Do you reject or fail to reject Ho at the 0.10 level of significance? O A. Reject Ho because the…
- Use technology to find the P-value for the hypothesis test described below. The claim is that for a smartphone carrier's data speeds at airports, the mean is μ = 11.00 Mbps. The sample size is n = 28 and the test statistic is t = 2.358.The P-value for a hypothesis test is shown. Use the P-value to decide whether to reject Ho when the level of significance is (a) a= 0.01, (b) a=0.05, and (c) a= 0.10. P=0.0596 (a) Do you reject or fail to reject Ho at the 0.01 level of significance? OA Fail to reject Hg because the P-value, 0.0596, is greater than a= 0.01. OB. Reject Ho because the P-value, 0.0596, is greater than a= 0.01. OC. Fail to reject Hg because the P-value, 0.0596, is less than a=0.01. %3D OD. Reject Ho because the P-value, 0.0596, is less than a= 0.01. %3DThe p-value for a hypothesis test turns out to be 0.0534. At a 3% level of sigrnificance, what is the proper decision? O Reject Ho O Fail to reject Ho Check Answer e Type here to search