The set is a basis for a subspace W. Use the Gram-Schmidt process to produce an orthogonal basis for W. Assume the vectors are in the order x, and x,. 1 3 1 2 - 7 1 1 The orthogonal basis produced using the Gram-Schmidt process for W is { }. (Use a comma to separate vectors as needed.)

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Chapter2: Second-order Linear Odes
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### Orthogonal Basis Using Gram-Schmidt Process

**Objective:**
To find the orthogonal basis for a subspace \( W \) using the Gram-Schmidt process.

**Given:**
The following set of vectors form a basis for a subspace \( W \):

\[
\mathbf{x_1} =
\begin{pmatrix}
1 \\
-1 \\
0 \\
1
\end{pmatrix}
, \quad
\mathbf{x_2} =
\begin{pmatrix}
3 \\
-2 \\
-7 \\
1
\end{pmatrix}
\]

**Step-by-Step Process:**

1. **Starting with \(\mathbf{x_1}\):**

Set \(\mathbf{u_1} = \mathbf{x_1}\).

2. **Making \(\mathbf{x_2}\) orthogonal to \(\mathbf{u_1}\):**

Compute the projection of \(\mathbf{x_2}\) onto \(\mathbf{u_1}\):

\[
\text{proj}_{\mathbf{u_1}}\mathbf{x_2} = \frac{\mathbf{x_2} \cdot \mathbf{u_1}}{\mathbf{u_1} \cdot \mathbf{u_1}} \mathbf{u_1}
\]

Subtract this projection from \(\mathbf{x_2}\) to get \(\mathbf{u_2}\):

\[
\mathbf{u_2} = \mathbf{x_2} - \text{proj}_{\mathbf{u_1}}\mathbf{x_2}
\]

**Outcome:**
The orthogonal basis produced using the Gram-Schmidt process for \( W \) is as follows:

\[
\mathbf{u_1} = 
\begin{pmatrix}
1 \\
-1 \\
0 \\
1
\end{pmatrix}
, \quad
\mathbf{u_2} = \text{(Calculated as per the steps above)}
\]

For the actual values of \(\mathbf{u_2}\), you would proceed with the calculation steps explicitly to find the specific orthogonal vectors.

**Note:** Remember to use a comma to separate the vectors when listing the orthogonal basis vectors.

---

This example illustrates the application of the Gram-Schmidt process to transform a basis into an orthogonal basis, enhancing understanding for students studying linear algebra concepts on an
Transcribed Image Text:### Orthogonal Basis Using Gram-Schmidt Process **Objective:** To find the orthogonal basis for a subspace \( W \) using the Gram-Schmidt process. **Given:** The following set of vectors form a basis for a subspace \( W \): \[ \mathbf{x_1} = \begin{pmatrix} 1 \\ -1 \\ 0 \\ 1 \end{pmatrix} , \quad \mathbf{x_2} = \begin{pmatrix} 3 \\ -2 \\ -7 \\ 1 \end{pmatrix} \] **Step-by-Step Process:** 1. **Starting with \(\mathbf{x_1}\):** Set \(\mathbf{u_1} = \mathbf{x_1}\). 2. **Making \(\mathbf{x_2}\) orthogonal to \(\mathbf{u_1}\):** Compute the projection of \(\mathbf{x_2}\) onto \(\mathbf{u_1}\): \[ \text{proj}_{\mathbf{u_1}}\mathbf{x_2} = \frac{\mathbf{x_2} \cdot \mathbf{u_1}}{\mathbf{u_1} \cdot \mathbf{u_1}} \mathbf{u_1} \] Subtract this projection from \(\mathbf{x_2}\) to get \(\mathbf{u_2}\): \[ \mathbf{u_2} = \mathbf{x_2} - \text{proj}_{\mathbf{u_1}}\mathbf{x_2} \] **Outcome:** The orthogonal basis produced using the Gram-Schmidt process for \( W \) is as follows: \[ \mathbf{u_1} = \begin{pmatrix} 1 \\ -1 \\ 0 \\ 1 \end{pmatrix} , \quad \mathbf{u_2} = \text{(Calculated as per the steps above)} \] For the actual values of \(\mathbf{u_2}\), you would proceed with the calculation steps explicitly to find the specific orthogonal vectors. **Note:** Remember to use a comma to separate the vectors when listing the orthogonal basis vectors. --- This example illustrates the application of the Gram-Schmidt process to transform a basis into an orthogonal basis, enhancing understanding for students studying linear algebra concepts on an
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