The series converges because lim n→∞o √31 (Type an exact answer, using radicals as needed.) 4 √31 n→∞o n = 0. The sum of the series is The series diverges because lim #0 or fails to exist. The series diverges because it is a geometric series with |r| 21. The series converges because it is a geometric series with |r|<1. The sum of the series is

Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
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Determine whether the series series attatched converges or diverges. if it converges find its sum.

 

Possible answers atatched

The series converges because lim
n→∞o
√31
(Type an exact answer, using radicals as needed.)
4
√31
n→∞o
n
= 0. The sum of the series is
The series diverges because lim
#0 or fails to exist.
The series diverges because it is a geometric series with |r| 21.
The series converges because it is a geometric series with |r|<1. The sum of the series is
Transcribed Image Text:The series converges because lim n→∞o √31 (Type an exact answer, using radicals as needed.) 4 √31 n→∞o n = 0. The sum of the series is The series diverges because lim #0 or fails to exist. The series diverges because it is a geometric series with |r| 21. The series converges because it is a geometric series with |r|<1. The sum of the series is
Σ
ΠΙΟ
4
√31
Transcribed Image Text:Σ ΠΙΟ 4 √31
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