The sequence {1,2,3,5,8,13,21,...} satisfies the difference equation Xn+2=Xn+1+Xp where Xo=1 and X1=2, whose solution is shown below. Try finding the new solution if we index the sequence ahead by 1 i.e. recompute the constants starting with Xo=2 and X1=3. Try it again where Xo=3 and X1=5. Do you see a pattern? So then, what is the solution after indexing m steps ahead i.e. if the mth member in the sequence is re-indexed to be the oth member? 1+ v5 )* 1 – V5 n 5 + 3/5 5 – 3/5 Xn 10 10

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Chapter2: Second-order Linear Odes
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The sequence {1,2,3,5,8,13,21,.} satisfies the difference equation Xp+2=Xp+1+Xp
where Xo=1 and X1=2, whose solution is shown below. Try finding the new solution
if we index the sequence ahead by 1 i.e. recompute the constants starting with Xo=2
and X1=3. Try it again where Xo=3 and X1=5. Do you see a pattern? So then, what is
the solution after indexing m steps ahead i.e. if the mth member in the sequence is
re-indexed to be the oth member?
5 – 3/5
+
n
5 + 3/5
1 + V5
1 – V5
10
10
2
m+n
m+n
5 + V5
1+ v5
5 – V5
- V5
X, =
10
2
10
Transcribed Image Text:The sequence {1,2,3,5,8,13,21,.} satisfies the difference equation Xp+2=Xp+1+Xp where Xo=1 and X1=2, whose solution is shown below. Try finding the new solution if we index the sequence ahead by 1 i.e. recompute the constants starting with Xo=2 and X1=3. Try it again where Xo=3 and X1=5. Do you see a pattern? So then, what is the solution after indexing m steps ahead i.e. if the mth member in the sequence is re-indexed to be the oth member? 5 – 3/5 + n 5 + 3/5 1 + V5 1 – V5 10 10 2 m+n m+n 5 + V5 1+ v5 5 – V5 - V5 X, = 10 2 10
т-п
(5 – 3/5
+
1 – V5
m-n
5 + 3/5
1 + V5
Xn =
10
10
2
The answer is not in the list.
m+n
m+n
5 + 3/5
1+ v5
5 – 3/5
+
1 – V5
Xn =
10
2
10
2
(*)() ()()"
5 – 3/5
+
5 + 3V5
n-m
п-т
1 + v5
1
V5
10
2
10
2
m+n
m+n
5 – 3/5
1 + v5
5 + 3V5
1 – V5
Xn =
10
2
10
Transcribed Image Text:т-п (5 – 3/5 + 1 – V5 m-n 5 + 3/5 1 + V5 Xn = 10 10 2 The answer is not in the list. m+n m+n 5 + 3/5 1+ v5 5 – 3/5 + 1 – V5 Xn = 10 2 10 2 (*)() ()()" 5 – 3/5 + 5 + 3V5 n-m п-т 1 + v5 1 V5 10 2 10 2 m+n m+n 5 – 3/5 1 + v5 5 + 3V5 1 – V5 Xn = 10 2 10
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