The second term is ---Select--- the first term, and both terms are perfect ---Select-- . Therefore we can identify the expression as which of the following? difference of squares Osum of cubes O difference of cubes
The second term is ---Select--- the first term, and both terms are perfect ---Select-- . Therefore we can identify the expression as which of the following? difference of squares Osum of cubes O difference of cubes
Algebra and Trigonometry (6th Edition)
6th Edition
ISBN:9780134463216
Author:Robert F. Blitzer
Publisher:Robert F. Blitzer
ChapterP: Prerequisites: Fundamental Concepts Of Algebra
Section: Chapter Questions
Problem 1MCCP: In Exercises 1-25, simplify the given expression or perform the indicated operation (and simplify,...
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![Step 1
We must identify the given polynomial \(27d^3 - 64\) as a difference of squares, as a sum of cubes, or as a difference of cubes. Knowing this will help us factor the polynomial.
Completely factor each term.
\[27d^3 = \left( \_\_\_ \right)^3 d^3\]
\[64 = \left( \_\_\_ \right)^6\]
Since the exponents of all factors are divisible by 3, each term can be written as a perfect cube.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F22926f56-41bb-43d5-b1fa-42be8a3ae12e%2Fc10b9b27-fd01-4e99-9ea5-54382ba1e0f4%2Frmjilek_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Step 1
We must identify the given polynomial \(27d^3 - 64\) as a difference of squares, as a sum of cubes, or as a difference of cubes. Knowing this will help us factor the polynomial.
Completely factor each term.
\[27d^3 = \left( \_\_\_ \right)^3 d^3\]
\[64 = \left( \_\_\_ \right)^6\]
Since the exponents of all factors are divisible by 3, each term can be written as a perfect cube.
![Identify as a difference of squares, or as a sum or difference of cubes.
The second term is [Select] the first term, and both terms are perfect [Select]. Therefore we can identify the expression as which of the following?
- \( \bigcirc \) difference of squares
- \( \bigcirc \) sum of cubes
- \( \bigcirc \) difference of cubes](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F22926f56-41bb-43d5-b1fa-42be8a3ae12e%2Fc10b9b27-fd01-4e99-9ea5-54382ba1e0f4%2F7akuqt_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Identify as a difference of squares, or as a sum or difference of cubes.
The second term is [Select] the first term, and both terms are perfect [Select]. Therefore we can identify the expression as which of the following?
- \( \bigcirc \) difference of squares
- \( \bigcirc \) sum of cubes
- \( \bigcirc \) difference of cubes
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