The second page is an example how it suppose to be done.(Hex-4-en-3-one+CH3CH2MgBR). It's complete. Please follow directions. bb. acetyl chloride + 2 equivalents of methylamine1. React the carbonyl compound:It is (circle one) CONJUGATEDNON-CONJUGATEDThe Nucleophile isPotential to Establish a Resonance SystemOption 1: Almost all reactionsOption 2: When Nu is a strong base (OH or OR),1 (Preferred)and the leaving group is identical to the Nu(option 1 is react the electron-rich nucleophilewith the electron- deficient carbonyl carbon)(option 2 is remove the alpha hydrogen andcreate a resonance-stabilized carbanion that canact as a nucleophile.)Circle the option and reason for reacting with aparticular site of the carbonyl compoundOption 1: Always use UNLESSOption 2: The Nu matches Y AND is -OR2. Take care of the negative formal charge of the oxygen in the tetrahedral complexOption 1 (Preferred): All cases except Option 21 (Preferred)Option 2: If there are no leaving groups,or if the only potential leaving group isthe Nu that was just added and itis not a very good leaving group (N or O).(option 1 is reform the double bond)(option 2 is add a hydrogen ion)Circle the option and reason* if you reform the Double bondWhats theReason?Option 1: Always use UNLESS- LeGuing group?- Shells ?- elec tronegativity?Ew A/ Reasomaue?charge ?Option 2: There is no leaving group (there arecarbons and hydrogens), OR there are onlycarbons and hydrogens except for the Nu thatjust added, AND it is N or O.3. Check to see if the reaction continues(xs Nu, or C with 4 single bonds, 2 electron-withdrawing atoms with non-bonded electron pairs.) CH3 -CH 2CH=cH-CHzz. hex-4-en-3-one + CH3CH2MgBr1. React the carbonyl compound:It is (circle one) CONJUGATED NON-CONJUGATEDCH- CH2The Nucleophile isCH3- CH= ě - cH = CH;-CHtsResonance SystemOption 1: Only the Nu createdfrom RMgBr, NaBH or LIAIH, sticksRR-CH CH8+Option 2 All other Nu end up here eventually1 (Preferred)NUBCHg-CH,(option 1 is react the electron-rich nucleophilewith the electron- deficient carbonyl carbon)(option 2 is to react the electron-rich nucleophilewith the slightly electron-deficient carbon at theend of the resonance system.)Circle the option and reason for reacting with aparticular site of the carbonyl compoundOption 1: RMgBr, LIAIH4, or NaBH4Option 2: All other Nu end up sticking here2. Take care of the negative formal charge of the oxygen in the tetrahedral complex:0:a Ht- CH-CH-CH3CH2-CH3Option 1 (Prefered). All cases except Option 21 (Preferred)Option 2: If there are no leaving groups,or if the only potential leaving group isthe Nu that was just added and itis not a very good leaving group (N or O).(option 1 is reform the double bond)(option 2 is add a hydrogen ion)Circle the option and reasonOption 1: Always use UNLESS* if u reform the DOuble bondyouOption 2: There is no leaving group (there arewhots tleReason?carbons and hydrogens), OR there are onlycarbons and hydrogens except for the Nu thatEw A/ ReaSonae?- LeGuing group?- Shells ?elec trinegativity?just added, AND it is N or O.|charge3. Check to see if the reaction continues (xs Nu, or C with 4 single bonds, 2 electron-withdrawing atoms with non-bonded electronpairs.)

The equation would normally be written: You can think of primary amines as just being modified…

Answered: The second page is an example how it…

The second page is an example how it suppose to be done. (Hex-4-en-3-one+CH3CH2MgBR). It's complete. Please follow directions.

Organic Chemistry: A Guided Inquiry

2nd Edition

ISBN:9780618974122

Author:Andrei Straumanis

Publisher:Andrei Straumanis

Chapter13: Substitution

Section: Chapter Questions

Problem 29CTQ

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Concept explainers

Alkanes and Cycloalkanes

Alkanes are saturated organic compounds which are made up of C and H atoms. Alkanes have the general formula of CnH2n+2. Alkane contains sp3 hybridized carbon atoms with four sigmas (σ) bonds & every hydrogen atom is connected with one of the carbon atoms. The size of the alkane could be determined by the number of carbon atoms located in it.

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The second page is an example how it suppose to be done.

(Hex-4-en-3-one+CH3CH2MgBR). It's complete. Please follow directions.

bb. acetyl chloride + 2 equivalents of methylamine
1. React the carbonyl compound:
It is (circle one) CONJUGATED
NON-CONJUGATED
The Nucleophile is
Potential to Establish a Resonance System
Option 1: Almost all reactions
Option 2: When Nu is a strong base (OH or OR),
1 (Preferred)
and the leaving group is identical to the Nu
(option 1 is react the electron-rich nucleophile
with the electron- deficient carbonyl carbon)
(option 2 is remove the alpha hydrogen and
create a resonance-stabilized carbanion that can
act as a nucleophile.)
Circle the option and reason for reacting with a
particular site of the carbonyl compound
Option 1: Always use UNLESS
Option 2: The Nu matches Y AND is -OR
2. Take care of the negative formal charge of the oxygen in the tetrahedral complex
Option 1 (Preferred): All cases except Option 2
1 (Preferred)
Option 2: If there are no leaving groups,
or if the only potential leaving group is
the Nu that was just added and it
is not a very good leaving group (N or O).
(option 1 is reform the double bond)
(option 2 is add a hydrogen ion)
Circle the option and reason
* if you reform the Double bond
Whats the
Reason?
Option 1: Always use UNLESS
- LeGuing group?
- Shells ?
- elec tronegativity?
Ew A/ Reasomaue?
charge ?
Option 2: There is no leaving group (there are
carbons and hydrogens), OR there are only
carbons and hydrogens except for the Nu that
just added, AND it is N or O.
3. Check to see if the reaction continues
(xs Nu, or C with 4 single bonds, 2 electron-withdrawing atoms with non-bonded electron pairs.)

CH3 -CH 2CH=cH-CHz
z. hex-4-en-3-one + CH3CH2MgBr
1. React the carbonyl compound:
It is (circle one) CONJUGATED NON-CONJUGATED
CH- CH2
The Nucleophile is
CH3- CH
= ě - cH = CH;-CHts
Resonance System
Option 1: Only the Nu created
from RMgBr, NaBH or LIAIH, sticks
R
R-CH CH
8+
Option 2 All other Nu end up here eventually
1 (Preferred)
NUB
CHg-CH,
(option 1 is react the electron-rich nucleophile
with the electron- deficient carbonyl carbon)
(option 2 is to react the electron-rich nucleophile
with the slightly electron-deficient carbon at the
end of the resonance system.)
Circle the option and reason for reacting with a
particular site of the carbonyl compound
Option 1: RMgBr, LIAIH4, or NaBH4
Option 2: All other Nu end up sticking here
2. Take care of the negative formal charge of the oxygen in the tetrahedral complex
:0:a Ht
- CH-CH-CH3
CH2-CH3
Option 1 (Prefered). All cases except Option 2
1 (Preferred)
Option 2: If there are no leaving groups,
or if the only potential leaving group is
the Nu that was just added and it
is not a very good leaving group (N or O).
(option 1 is reform the double bond)
(option 2 is add a hydrogen ion)
Circle the option and reason
Option 1: Always use UNLESS
* if u reform the DOuble bond
you
Option 2: There is no leaving group (there are
whots tle
Reason?
carbons and hydrogens), OR there are only
carbons and hydrogens except for the Nu that
Ew A/ ReaSonae?
- LeGuing group?
- Shells ?
elec trinegativity?
just added, AND it is N or O.
|
charge
3. Check to see if the reaction continues (xs Nu, or C with 4 single bonds, 2 electron-withdrawing atoms with non-bonded electron
pairs.)

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