The second member of Balmer series of hydrogen atom has wavelength 4860 A°. Calculate Rydberg's constant. Hence, calculate the energy in ev when X election is orbiting in the third Bohr orbit Planck's constant = 6.63 × 10 -34 Jg Speed of light = 3 × 108 m/s 1 eV = 1·6 x 10 ¹⁹ J
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- Which of these expressions would yield the wavelength of light in meters emitted when an electron drops from orbit n = 3 to n = 2 in a Bohr hydrogen atom? Given h = 4.14 x 10-15 eVs and c = 3.00 x 108m/s. a. 1.89 x h x c b. hc/3.4 c. (1.51 + 3.4)/hc d. hc/1.89 e. 1.89/hxcAn electron is in the n = 4 orbit of an hydrogen atom. It returns to the ground state with emission of light. The Rydberg constant is R = 1.097 x 107 m-1. What is the frequency of the light emitted? Select one: a. 2.74 x 1014 Hz b. 8.23 x 106 Hz c. 3.08 x 1015 Hz d. 10.28 x 106 Hzご A 国 Using the Rydberg equation provided below determine the wavelength as well as the energy for a single photon emitted by the hydrogen atom's electron moving fromn 6 to n = 2. (more than one choice) %3D 1 = 1.10x10' m 1 1 where n>m 1 E=h c where h=6.63x10-3* J•s c=3.00 x10° m/s
- An electron is orbiting in the n = 3 orbit of an hydrogen atom. It is promoted by absorption of light energy to the n = 4 level. The Rydberg constant is R = 1.097 x 107 m-1. What is the wavelength of the light absorbed? Select one: a. 427 nm b. 1.094 μm c. 1.875 μm d. 763 nmWhat is the wavelength of the radiation absorbed when an electron move from n = 2 to n = 5 for a helium +1 ion?What wavelength of light is emitted by a hydrogen atom in which an electron makes a transition from the n = 8 to the n = 5 state? Enter this wavelength expressed in nanometers. 1 nm = 1 x 10-9 m Assume the Bohr model.