The Second Derivative Test cannot be used to conclude that x = 2 is the location of a relative minimum or relative maximum for which of the following func A f (x) = cos (x – 2), where f' (x) = – sin(x – 2) f (x) = xe¯7, where f' (x) = e xe C f (x) = x2 – 4x – 2, where f' (x) = 2x – 4 f (x) = x3 – 6x? + 12x + 1, where f' (x) = 3x2 – 12x + 12

Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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The Second Derivative Test cannot be used to conclude that x =
2 is the location of a relative minimum or relative maximum for which of the following functions?
A
f (æ)
= cos (x – 2), where f' (x) = – sin(x – 2)
-
f (x)
2, where f' (x) = ei -
B
= xe
xe
f (x) = x² – 4x – 2, where f' (x) = 2x – 4
D
f (x) = x³ – 6x² + 12x + 1, where f' (x) = 3x² – 12x + 12
Transcribed Image Text:The Second Derivative Test cannot be used to conclude that x = 2 is the location of a relative minimum or relative maximum for which of the following functions? A f (æ) = cos (x – 2), where f' (x) = – sin(x – 2) - f (x) 2, where f' (x) = ei - B = xe xe f (x) = x² – 4x – 2, where f' (x) = 2x – 4 D f (x) = x³ – 6x² + 12x + 1, where f' (x) = 3x² – 12x + 12
Expert Solution
Step 1

We need to check for which of the given functions, can't conclude about

location of  a relative minimum or relative maximum at x=2 using second derivative test.

Second Derivative test:

  • If f'c=0 and f''c>0, then there is a local minimum at x=c.
  • If f'c=0 and f''c<0, then there is a local maximum at x=c.
  • If f'c=0 and f''c=0 or f''c doesn't exist, then the test is inconclusive. i.e., x=c might be a point of local minimum or local maximum or a point of inflection.

We have to now check that, at x=2 which of the given functions satisfy the 3rd condition of the second derivative test.

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