The scatter plot shows the time spent texting, x, and the time spent exercising, y, by each of 23 students last week. (a) Write an approximate equation of the line of best fit for the data. It doesn't have to be the exact line of best fit. (b) Using your equation from part (a), predict the time spent exercising for a student who spends 6 hours texting. Note that you can use the graphing tools to help you approximate the line. Time spent exercising (in hours) y 10- 9- 8+x 7+ 6 5. 3- 2 0 x X X x X x X X X Time spent texting (in hours) X xx 9 X 10 X ? (a) Write an approximate equation of the line of best fit. 0 y = (b) Using your equation from part (a), predict the time spent exercising for a student who spends 6 hours texting. hours X ?

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### Analyzing the Relationship Between Time Spent Texting and Exercising

The scatter plot shows the time spent texting, \(x\), and the time spent exercising, \(y\), by each of 23 students last week.

#### Tasks:
(a) Write an approximate equation of the line of best fit for the data. It doesn't have to be the exact line of best fit.

(b) Using your equation from part (a), predict the time spent exercising for a student who spends 6 hours texting.

Note that you can use the graphing tools to help you approximate the line.

#### Scatter Plot Overview:

- **X-axis:** Time spent texting (in hours), ranging from 0 to 10 hours.
- **Y-axis:** Time spent exercising (in hours), ranging from 0 to 10 hours.
- **Data Points:** Represent the correlation between the time students spent texting and exercising. Each 'x' mark on the graph represents a student. 

#### Exercising (in hours) vs Texting (in hours):

From the scatter plot, there appears to be a negative correlation between the time spent texting and the time spent exercising. As the time spent texting increases, the time spent exercising tends to decrease.

#### Example Solution:

(a) **Approximate Equation of the Line of Best Fit:**

Using a general observation of the scatter plot points, a line of best fit could be approximated. The slope and the y-intercept of this line can be estimated by selecting two points on the line and calculating their differences.

Suppose two points on this line are (1, 8) and (9, 2). The slope \(m\) can be calculated as:
\[ m = \frac{2 - 8}{9 - 1} = \frac{-6}{8} = -0.75 \]

Using the slope-intercept form \(y = mx + b\), substitute one of the points to solve for \(b\), the y-intercept.

Using point (1, 8):
\[ 8 = -0.75(1) + b \]
\[ 8 = -0.75 + b \]
\[ b = 8 + 0.75 = 8.75 \]

Therefore, the approximate equation is:
\[ y = -0.75x + 8.75 \]

(b) **Prediction for 6 Hours Texting:**

Using the equation from part (a),
Transcribed Image Text:### Analyzing the Relationship Between Time Spent Texting and Exercising The scatter plot shows the time spent texting, \(x\), and the time spent exercising, \(y\), by each of 23 students last week. #### Tasks: (a) Write an approximate equation of the line of best fit for the data. It doesn't have to be the exact line of best fit. (b) Using your equation from part (a), predict the time spent exercising for a student who spends 6 hours texting. Note that you can use the graphing tools to help you approximate the line. #### Scatter Plot Overview: - **X-axis:** Time spent texting (in hours), ranging from 0 to 10 hours. - **Y-axis:** Time spent exercising (in hours), ranging from 0 to 10 hours. - **Data Points:** Represent the correlation between the time students spent texting and exercising. Each 'x' mark on the graph represents a student. #### Exercising (in hours) vs Texting (in hours): From the scatter plot, there appears to be a negative correlation between the time spent texting and the time spent exercising. As the time spent texting increases, the time spent exercising tends to decrease. #### Example Solution: (a) **Approximate Equation of the Line of Best Fit:** Using a general observation of the scatter plot points, a line of best fit could be approximated. The slope and the y-intercept of this line can be estimated by selecting two points on the line and calculating their differences. Suppose two points on this line are (1, 8) and (9, 2). The slope \(m\) can be calculated as: \[ m = \frac{2 - 8}{9 - 1} = \frac{-6}{8} = -0.75 \] Using the slope-intercept form \(y = mx + b\), substitute one of the points to solve for \(b\), the y-intercept. Using point (1, 8): \[ 8 = -0.75(1) + b \] \[ 8 = -0.75 + b \] \[ b = 8 + 0.75 = 8.75 \] Therefore, the approximate equation is: \[ y = -0.75x + 8.75 \] (b) **Prediction for 6 Hours Texting:** Using the equation from part (a),
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