The sample space of an experiment consists of the following outcomes: S = {1, 5, 7} The following events are defined: • X = The outcome of the experiment is an even number Y = {1,5} Z= {1,7} We are also given the following information: X, Y and Z are independent events P(Y UZ) = 1/2 Probabilities of all numbered outcomes are equal. In other words:

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### Sample Space and Event Definition in Probability

**Sample Space:**

The sample space of an experiment consists of the following outcomes:

\[ S = \{1, 5, 7\} \]

**Defined Events:**

- **X**: The outcome of the experiment is an even number
- **Y**: \(\{1, 5\}\)
- **Z**: \(\{1, 7\}\)

**Given Information:**

- **X, Y, and Z** are independent events
- \( P(Y \cup Z) = \frac{1}{2} \)
- Probabilities of all numbered outcomes are equal: \[ P(1) = P(5) = P(7) \]

**Tasks:**

A. **Venn Diagram:**

Draw a Venn Diagram to represent events X, Y, Z, and all outcomes in the sample space \( S \). If an event does not exist, it can be placed outside of \( S \) or not included—this implies nonexistent events have zero likelihood.

B. **Numerical Calculation:**

Compute the numerical value of \( P(X \cup Y \cup Z) \).

**Hint**: Use the formula for a triple union:

\[
P(X \cup Y \cup Z) = P(X) + P(Y) + P(Z) - P(X \cap Y) - P(X \cap Z) - P(Y \cap Z) + P(X \cap Y \cap Z)
\]
Transcribed Image Text:### Sample Space and Event Definition in Probability **Sample Space:** The sample space of an experiment consists of the following outcomes: \[ S = \{1, 5, 7\} \] **Defined Events:** - **X**: The outcome of the experiment is an even number - **Y**: \(\{1, 5\}\) - **Z**: \(\{1, 7\}\) **Given Information:** - **X, Y, and Z** are independent events - \( P(Y \cup Z) = \frac{1}{2} \) - Probabilities of all numbered outcomes are equal: \[ P(1) = P(5) = P(7) \] **Tasks:** A. **Venn Diagram:** Draw a Venn Diagram to represent events X, Y, Z, and all outcomes in the sample space \( S \). If an event does not exist, it can be placed outside of \( S \) or not included—this implies nonexistent events have zero likelihood. B. **Numerical Calculation:** Compute the numerical value of \( P(X \cup Y \cup Z) \). **Hint**: Use the formula for a triple union: \[ P(X \cup Y \cup Z) = P(X) + P(Y) + P(Z) - P(X \cap Y) - P(X \cap Z) - P(Y \cap Z) + P(X \cap Y \cap Z) \]
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