The sales by Walker's Milk and Dairy products, in millions of dollars, for the seven-year period from 2014 to 2020 are reported in thefollowing table.Year2014201520162017201820192020Y' =Sales ($ millions)$17.8a. Determine the least squares trend equation. (Round the final answers in millions of dollars to 2 decimal places.)19.722.4tEstimate sales for 202124.024.727.529.2b. Estimate sales for 2021. (Round the intermediate calculations and the final answer in millions of dollars to 2 decimal places.)($ million).

The question is about time series.Given :To find :a ) Least square trend equationb ) Estimated sales…

Answered: The sales by Walker's Milk and Dairy…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Consider the following. x 1 2 3 4 y 4 6 9 13 (a) Find an equation of the least-squares line for the data. (Give each answer correct to 3 decimal places.)y = x +(b) Draw a scatter diagram for the data and graph the least-squares line.
The following table gives the personal savings (in billions of dollars) in the United States for selected years. Year 2005 2010 2011 2012 2013 2014 2015 2016 Personal Savings (billions) $153.8 189.3 187.5 142.0 155.7 152.1 175.6 199.6 5. Find the average rate of change between the years 2010 and 2012. 6. Interpret questions 4 and 5 on the graph. 7. Find the point of inflection of the regression equation and interpret what it means.
The table lists the average tuition and fees at private colleges and universities for selected years. Year 1985 1990 1995 2000 2008 5311 25,115 Tuition and Fees (in dollars) 9375 SO 12,418 (a) Find the equation of the least-squares regression line that models the data. y 840.450 (Type the slope as a decimal rounded to three decimal places. Round the y-intercept to the nearest integer.) (b) Graph the data and the regression line in the same viewing window using the parameters given below the graph choices. Choose the correct graph below. OA. O B. o HE RO OC. 16,230 A o ƠN
The following table gives estimates of the percent of a certain country's population below the poverty level for 1998–2008. Year Percent 1998 12.8 2000 11.2 2002 12.1 2004 12.7 2006 12.9 2008 13.2 Find the least squares line that relates years to percent below the poverty level. (Let x = 0 represent the year 1998. Enter a mathematical expression.
(e) Find the least-squares regression line treating square footage as the explanatory variable.
a) Determine the least squares regression equation for the population in years since 2005. Round the slope and y-intercept to the nearest tenth. b) Find the correlation coefficient, r-value, of the line. Round your answer to the nearest thousandth. c) Predict the population for the 2020. ____ thousand people
How much of the variation in average annual energy expenditures is explained by the least-squares regression line? Round the answer to at least one decimal place.
he table shows the minimum wage rates for the United States during different years. Year 1978 1979 1980 1990 1991 1996 1997 2007 2008 2009 Minimum hourly wage ($) 2.65 2.90 3.35 3.80 4.25 4.75 5.15 5.85 6.55 7.25 Write the least squares regression equation that models the data. Let x = time in years since 1900 and let y = minimum hourly wage. Use the equation to estimate the minimum hourly wage of a U.S. worker in 2025. Show your work. Answer:
Researchers are investigating how the amount of monthly rainfall, measured in centimeters (cm), affects the monthly growth, in cm, of a certain plant. From a sample of data, the researchers created a least- squares regression line. Computer output is shown in the following table. Variable DF Estimate SE T Intercept 1 0.75 0.350 2.14 Rainfall 1 0.15 0.025 6.00 Which of the following statements is an interpretation of the value 0.75 shown in the table? A Monthly growth is expected to increase by 0.75 cm when rainfall increases by 1 cm. Rainfall is expected to increase by 0.75 cm when monthly growth increases by 1 cm. For a month with 0 cm of rainfall, the monthly growth is expected to be approximately 0.75 cm. For a plant with 0 cm of monthly growth, the month had an expected rainfall of approximately 0.75 cm. E Approximately 75% of the variability in monthly growth is due to its linear relationship with rainfall.

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