The root of the equation f (x) = 0 is found by using the Newton's method. The initial estimate of the root is xe = 3,f (3) = 3. The angle between the tangent to the function f (x) at x = 3 and the positive x-axis is 57°. The next estimate of the root, x, is most nearly -0.24704 0.4024 6.2470 1.0518
The root of the equation f (x) = 0 is found by using the Newton's method. The initial estimate of the root is xe = 3,f (3) = 3. The angle between the tangent to the function f (x) at x = 3 and the positive x-axis is 57°. The next estimate of the root, x, is most nearly -0.24704 0.4024 6.2470 1.0518
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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![4:31
ul LTE O
A docs.google.com
U.0000
0.00474
0.00014
0.081
The root of the equation f (x) = 0 is found by using the Newton's method. The initial
estimate of the root is xo = 3,f (3) = 3. The angle between the tangent to the
function f (x) at x = 3 and the positive x-axis is 57°. The next estimate of the root, x
is most nearly
-0.24704
0.4024
6.2470
1.0518
Given the function f(x). Suppose that the Newton's interpolating polynomial P:(x) of f(x) at
the points xo - 0, x, -1 and x2 - 2 is:
7
1
P,(x) =- 120** 120
Then f(xg, x1] =
1/20
-7/120
-1/20](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F99fc4f08-f6cb-4411-bbba-29e3424c10e5%2F6279a6ec-7633-455c-a44f-b25c8ad992a5%2Fqwj3np_processed.jpeg&w=3840&q=75)
Transcribed Image Text:4:31
ul LTE O
A docs.google.com
U.0000
0.00474
0.00014
0.081
The root of the equation f (x) = 0 is found by using the Newton's method. The initial
estimate of the root is xo = 3,f (3) = 3. The angle between the tangent to the
function f (x) at x = 3 and the positive x-axis is 57°. The next estimate of the root, x
is most nearly
-0.24704
0.4024
6.2470
1.0518
Given the function f(x). Suppose that the Newton's interpolating polynomial P:(x) of f(x) at
the points xo - 0, x, -1 and x2 - 2 is:
7
1
P,(x) =- 120** 120
Then f(xg, x1] =
1/20
-7/120
-1/20
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