The room is very cool at a constant temperature of 5°C. While doing an autopsy early one morning on a murder victim, Doctor is killed and the cadaver that he is dissecting is stolen. At 10 a.m., the doctor’s assistant discovers his body and finds its temperature to be 23°C, and at noon the body’s temperature is down to 18.5°C. Assuming the doctor had a normal temperature of 37°C when he was alive, when was he murdered? Use Newton’s of Cooling(Differential Equation)
The room is very cool at a constant temperature of 5°C. While doing an autopsy early one morning on a murder victim, Doctor is killed and the cadaver that he is dissecting is stolen. At 10 a.m., the doctor’s assistant discovers his body and finds its temperature to be 23°C, and at noon the body’s temperature is down to 18.5°C. Assuming the doctor had a normal temperature of 37°C when he was alive, when was he murdered? Use Newton’s of Cooling(Differential Equation)
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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The room is very cool at a constant temperature of 5°C. While doing an autopsy early one morning on a murder victim, Doctor is killed and the cadaver that he is dissecting is stolen. At 10 a.m., the doctor’s assistant discovers his body and finds its temperature to be 23°C, and at noon the body’s temperature is down to 18.5°C. Assuming the doctor had a normal temperature of 37°C when he was alive, when was he murdered? Use Newton’s of Cooling(Differential Equation)
![Differential Equation:
dT
= k(T – Tm)
dt
Where:
dT
dt rate at which temperature changes
(Zill)
t = time
k = constant of proportionality
room temperature
Solution to the Differential Equation:
T(t) = Cekt + Tm
Where:
(Zill)
T(t) = temperature of the object at time t
C = constant](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fc3fe2d5f-162e-42c0-ada7-c25163783384%2Ff8a04fc4-dfc6-4019-ae59-ee1aa3abdd5f%2Fldeuby_processed.png&w=3840&q=75)
Transcribed Image Text:Differential Equation:
dT
= k(T – Tm)
dt
Where:
dT
dt rate at which temperature changes
(Zill)
t = time
k = constant of proportionality
room temperature
Solution to the Differential Equation:
T(t) = Cekt + Tm
Where:
(Zill)
T(t) = temperature of the object at time t
C = constant
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