The “Ring of Fire” is a popular fair ride in which riders complete a vertical circle of radius 8.0 m, going upside down in the process. Suppose a rider of mass 80.0 kg is seated on the ride and reaches a speed of 10.0 m/s at the top of the ride and 15.0 m/s at the bottom of the ride. The centripetal force follows the formulas for uniform circular motion at these two points even though the speed changes. (a) Find the range of normal force (seat acting on the rider) at these speeds. (b) What speed at the top of the loop would make the normal force zero? What does the person experience in that case?

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A: Given: The centripetal acceleration at a distance of 0.0141 m from the center is 317 m/s2. The…

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A: Why does the period T change? Explain:

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Q: 1. (a) What is the radius of a bobsled turn banked at 75° and taken at 34 m/s, assuming it is…

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A: Since we only answer up to 3 sub-parts, we’ll answer the first 3. Please resubmit the question and…

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A: Image-1

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Q: you in a car going around a horizontal corner:

A: Here you have asked for the answer to question 'g'.

Q: v = 34 m/s r= 33 m r= 24 m

A:

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Q: 9) A bicyclist rides on a circular track. The coefficient of friction between the wheels and the…

A: 9) coefficient of friction = 0.8constant speed = 15 m/sradius ??

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Q: 2. It takes a 615 kg car 14.3 s to travel at a uniform speed around a level circular path of 50.0 m…

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A: 1. The centripetal force here is the x-component of the Tension force which the parent applies on…

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Centripetal Force

A particle, body, object or certain mass while travelling in a rotational path or semicircular path, experiences an inertia force. If that inertia force pulls the towards the inward of the imaginary circle in the rotation, it is termed as centripetal force.