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The ring at Bis supported in equilibrium by spring AB, a cable running through the frictionless pulley at C, and cable BD. The pulley radius is 0.0180 m, and the unstretched length of spring AB is 0.24 m. If F₁ - 350 N and F-140 N at 0=34 degrees, determine the spring constant and the force exerted on the ring by cable BD expressed in Cartesian components. F₁ d C B k A

The ring at Bis supported in equilibrium by spring AB, a cable running through the frictionless pulley at C, and cable BD. The pulley radius is 0.0180 m, and the unstretched length of spring AB is 0.24 m. If F₁ - 350 N and F-140 N at 0=34 degrees, determine the spring constant and the force exerted on the ring by cable BD expressed in Cartesian components. F₁ d C B k A

Elements Of Electromagnetics
Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
Problem 1.1MA
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Need help please. Round answers to 3 sig figs please.
The ring at B is supported in equilibrium by spring AB, a cable running through the frictionless pulley at C, and cable BD. The pulley radius is 0.0180 m, and the unstretched length of spring AB is 0.24 m. If F₁ = 350 N and F₂ = 140 N at 0=34 degrees, determine the spring constant & and the force exerted on the ring by cable BD expressed in Cartesian components. F₁ d C d B k Jurid F2 0.180 m 0.0720 m C Values for dimensions on the figure are given in the following table. Note the figure may not be to scale. Variable Value a 0.400 m b 0.120 m k= 1653.1875 D Note the figure may not be to scale. FRD=-42.7 xN/m ✓+64.1 a *) N A
Transcribed Image Text:The ring at B is supported in equilibrium by spring AB, a cable running through the frictionless pulley at C, and cable BD. The pulley radius is 0.0180 m, and the unstretched length of spring AB is 0.24 m. If F₁ = 350 N and F₂ = 140 N at 0=34 degrees, determine the spring constant & and the force exerted on the ring by cable BD expressed in Cartesian components. F₁ d C d B k Jurid F2 0.180 m 0.0720 m C Values for dimensions on the figure are given in the following table. Note the figure may not be to scale. Variable Value a 0.400 m b 0.120 m k= 1653.1875 D Note the figure may not be to scale. FRD=-42.7 xN/m ✓+64.1 a *) N A
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