The rigid beam of negligible weight is supported by a pin at O and two vertical rods.Determine the elongation of the steel rod.BronzeSteel10 ft A = 0.5 in.²E = 29 × 10° psiA = 2 in.?E = 12 × 10° psi -- 3 ft-| 3 ft8 ft4 ft-150 kipsSelect one:O a. 0.31 inO b. 0.16 inO c. 0.39 inO d. 0.23 in

Given- l1=3ftl2=10ftA1=2in2E1=12×106A2=0.5 in2E2=29×106 Psi The diagram is given below

The rigid beam of negligible weight is supported by a pin at O and two vertical rods. Determine the elongation of the steel rod. Bronze A = 2 in.2 E = 12 x 10° psi- Steel 10 ft A = 0.5 in.? E = 29 × 10º psi -3 ft 3 ft 8 ft - 4 ft- 150 kips

The rigid beam of negligible weight is supported by a pin at O and two vertical rods. Determine the elongation of the steel rod. Bronze A = 2 in.2 E = 12 x 10° psi- Steel 10 ft A = 0.5 in.? E = 29 × 10º psi -3 ft 3 ft 8 ft - 4 ft- 150 kips

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

See similar textbooks

Similar questions

Each of the links AB and CD is made of steel (E = 29 x 106 psi) and has a uniform 1 rectangular cross section of x 1 in. Determine the largest load which can be suspended from 4 point E if the deflection of E is not to exceed 0.02 in. 8 in. A 8 in. B O A 10 in. D 17 in. E
The circular steel shaft is subjected to two torques as shown. The segment AB is hollow, with outside diameter of 1 inch and an inside diameter of ½ inch. The segment BC is solid, with a diameter of 1 inch. Determine (a) the maximum shear stress in the shaft, and (b) the angle of twist in degrees between A and C, using G = 12 x 10⁰ psi. 750-in. Ⓡ 2 ft 2000-in. 18 Itin. 3 ft Lin.
Determine the force in member BE of the loaded truss. The force is positive if in tension, negative if in compression. -10 15" 10'- B .C 10 10 15 L 2L 15 58 58 Answer: BE = i
< Title A (-7,-2) y, 44 1 5. The 1800-N force F is applied to the end of the I-beam. Express Fas a vector using the unit vectors I and j. F₁ = 3 kips 30° AL 45° B (8,6) F = 3000 lb --x, ft 6. The two structural members, one of which is in tension and the other in compression, exert the indicated forces on joint O. Determine the magnitude of the resultant R of the two forces and the angle which R makes with the positive x-axis 3 kN A F = 1800 N 7. The two forces shown act at point A of the bent bar. Determine the resultant R of the two forces 30° Q : ,2 kN F₂= 7 kips 8. The guy cables AB and AC are attached to the top of the transmission tower. The tension in cable AB is 8 kN. Determine the required tension Tin cable AC such that the net effect of the 1/17 2/17
1000 N 3000 N 1000 N b ЕЬ 1000 N a F D 30 В 2 m- -2 m- -2 m- -2 m- 4000 N 2000 N Determine the force in member EB of the roof truss shown by method of sections. Indicate whether the member is in tension or compression.
8m A 6M using in F B с 100KN 8m 6m Method of Sections determine forces FE, FC, BC
calcualte the forces in members PQ and QR. USE sections method.
Column AB carries a centric load P of magnitude 16.5 kips. Cables BC and BD are taut and prevent motion of point B in the xz plane. Using Euler's formula and a factor safety of 2.2 and neglecting the tension in the cables, determine the maximum allowable length L. Use E = 29 × 106 psi. (Round the final answer to one decimal place.) P B W10 X 22 D The maximum allowable length Lis ft.
A rigid ban AB and "CD" as shown are supported by pins at "A" & "C" and two ross. Determine the maximum force 'p' that can be applied as given if it's vertical movement is limited to 5 mm. Neglect the weight of all the members. www A 3m 3m Aluminium P L = 2m, A= 500m² E =70 GPA 3m IB 3m Steel L=2m A= 300m² E = 2006/ D
Find the force member DE. DE = KN. Compression -6 6*4 > |100 kN 75 kN 75 kN D 25 kN -25 kN E 3 C 4 F В I K H 14 G Dimensions in meters
3m 8 KN B 3m 4KN 8kN C K 3m 4KN 10kN kh 3m 4KN 8KN E 3m 8kN 4KN -3 m Gy Ay Solve the Ay and Gy of this symmetrical Howe truss. After that, solve it using METHOD OF SECTIONS. OSA шь