The rigid bar BDE is supported by two links AB and AD. Link AB is made of aluminum (E = 70 Gpa) and has a cross-sectional area of 500mm ^ 2; link CD is made of steel (E = 200 Gpa) and has a cross-sectional area of 600mm ^ 2, For the shown force of 30 KN, determine the displacement at point B, D, and E

The rigid bar BDE is supported by two links AB and AD. Link AB is made of aluminum (E = 70 Gpa) and has a cross-sectional area of 500mm ^ 2; link CD is made of steel (E = 200 Gpa) and has a cross-sectional area of 600mm ^ 2, For the shown force of 30 KN, determine the displacement at point B, D, and E

Related questions

Q: In (Figure 1), σy Figure = 49.1 MPa. Determine the principal stresses. Specify the orientation of…

A: Step 1: Step 2: Step 3: solution is given above Step 4:

Q: A thin rectangular plate is uniformly, deformed, as shown. Determine the shear strain Yxy at P.…

A: Solution: The shear strain of the thin rectangular sheet in the y-direction can be obtained using…

Q: What is the indentation diagonal length in in, when a load of 0.60 kg produces a Vickers HV of 400?

Q: 1. A rod is composed of three segments as shown in the figure and carries the axial loads P1= 120kN…

Q: f a compressional stress of 200.0 N is applied to a copper rod having a diameter of .500 cm and a…

Q: nd trim printed circuit sheets. For the position shown, determine the vertical component of the…

A: Px = 390 sin 13 = 87.73 NPy =390 cos 13 = 380 N(FBD)x =2510034 FBD(FBD)y =9710034FBD

Q: What torque

A: Given dataL=2.76m=2760mmInner diameter, c=3.313×10−2m=33.13mmSimilarly outer diameter b=76.63mmAngle…

Q: Two aluminum plates, each having a width of b = 5.6 in. and a thickness of t = 0.725 in., are welded…

Q: A 1.05-m-long rod of negligible weight is supported at its ends by wires A and B of equal length…

A: This question involves two concepts: (A) Free body diagram and subsequent condition for the static…

Q: The table below shows ultimate tensile strengths (Fu ) and Young's moduli (Y) for tungsten (W) and…

Q: A 7-kip · ft torque is applied to a hollow aluminum shaft having the cross section shown. Neglecting…

A: Given data- T=7 kip-ft Radius of outer circle, r0=7 in Radius of inner circle, ri=14 in-4 in-2 in2=4…

Q: A fishing rope of length (74+ 50) m has the diameter (74 + 5) mm. When a weight of (74 +200) N is…

A: i. The cross-sectional area of the rope is given by,

Q: The cross-sectional area of the bar is 5 cm?. Use E = 70 GPa for aluminum, and E = 200 GPa for…

Question

Formula Formula Bond dissociation energy (BDE) is the energy required to break a bond, making it an endothermic process. BDE is calculated for a particular bond and therefore consists of fragments such as radicals since it undergoes homolytic bond cleavage. For the homolysis of a X-Y molecule, the energy of bond dissociation is calculated as the difference in the total enthalpy of formation for the reactants and products. X-Y → X + Y BDE = Δ H f X + Δ H f Y – Δ H f X-Y where, ΔHf is the heat of formation.

Expert Solution

This question has been solved!

Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.

This is a popular solution!

SEE SOLUTION Check out a sample Q&A here

Concept and Principle:

VIEW

Calculation: Force

VIEW

Calculation: Displacement B

VIEW

Calculation: Displacement D

VIEW

Calculation: Displacement E

VIEW

Answer:

VIEW

Trending now

This is a popular solution!

Step by step

Solved in 6 steps with 3 images

SEE SOLUTION Check out a sample Q&A here

Similar questions

Find the elongation of a rod made of aluminum and copper under a tension of 5.8×103 N. The dimensions of the rod are R=0.5 cm, LAl=10.5 m, LCu=5.5 m (Young moduli are 7.0×1010 Pa for Al and 11×1010 Pa for Cu)
Member BC has a square cross section. The diameter of the pins at A and B are 3 cm and 2 cm respectively. If the allowable normal stress for member BC is allow = 25 MPa and the allowable shear stress for the pins iS Tallow = 12 MPa, calculate the maximum force intensity w (in N/m). 4 cm В 50° 3 m A W
H.W A uniform glass rod having a length L is placed in the smooth hemispherical bowl having a radius r. Determine the angle of inclination 0 for equilibrium. Ans: L+VL+128r 2NCOSO No 0 = cos %3D 16r Note: By observation = 0.
Problem Solving... The cross-sectional area of the bar is 5 cm2. Use E= 70 GPa for aluminum, and E= 200 GPa for steel. Aluminum Steel Aluminum 80 kN 20 kN 30 kN 70 kN A 3 m -4 m- 5 m- - What is the elongation in segment AB (Aluminum)? * -7.8571 x10^-3 m O6.8571 x10^-3 m O -6.8571 x10^-3 m 7.8571 x10^-3 m
Structural member AB is to be supported by a strut CD. Determine the smallest length CD may have, and specify where D must be located for a strut of this length to be used. Take x= 120 mm. 60 mm D. y 20 mm E The smallest length CD may have is mm. The coordinates of point Dare ( and Imm.