The reusable booster rockets of the space shuttle use a mixture of aluminum and ammonium perchlorate as fuel. A possible reaction is 3Al(s) + 3NH4ClO4(s) → Al₂O3 (s) + AlCl3 (s) + 3NO(g) + 6H₂O(g) Calculate AH for this reaction. Substance and State AH (kJ/mol) Al(s) 0 Al2O3(s) AlCl3 (8) H₂O(g) NO(g) NH4C1O4(s) AH° = Submit Answer -1676 -704 -242 90. -295 Try Another Version item attempt remaining
Thermochemistry
Thermochemistry can be considered as a branch of thermodynamics that deals with the connections between warmth, work, and various types of energy, formed because of different synthetic and actual cycles. Thermochemistry describes the energy changes that occur as a result of reactions or chemical changes in a substance.
Exergonic Reaction
The term exergonic is derived from the Greek word in which ‘ergon’ means work and exergonic means ‘work outside’. Exergonic reactions releases work energy. Exergonic reactions are different from exothermic reactions, the one that releases only heat energy during the course of the reaction. So, exothermic reaction is one type of exergonic reaction. Exergonic reaction releases work energy in different forms like heat, light or sound. For example, a glow stick releases light making that an exergonic reaction and not an exothermic reaction since no heat is released. Even endothermic reactions at very high temperature are exergonic.
![### Calculating the Enthalpy Change of a Reaction
**Context:**
The reusable booster rockets of the space shuttle use a mixture of aluminum and ammonium perchlorate as fuel. A possible reaction is:
\[
3\text{Al}(s) + 3\text{NH}_4\text{ClO}_4(s) \rightarrow \text{Al}_2\text{O}_3(s) + \text{AlCl}_3(s) + 3\text{NO}(g) + 6\text{H}_2\text{O}(g)
\]
**Objective:**
Calculate the standard enthalpy change (\( \Delta H^\circ \)) for this reaction.
**Data:**
The following table lists the standard enthalpies of formation (\( \Delta H_f^\circ \)) for the substances involved in the reaction:
| Substance and State | \( \Delta H_f^\circ \) (kJ/mol) |
|---------------------|-------------------------|
| Al(s) | 0 |
| Al\(_2\)O\(_3\)(s) | -1676 |
| AlCl\(_3\)(s) | -704 |
| H\(_2\)O(g) | -242 |
| NO(g) | 90 |
| NH\(_4\)ClO\(_4\)(s) | -295 |
**Calculation:**
To find the overall enthalpy change of the reaction (\( \Delta H^\circ \)), apply the following formula:
\[
\Delta H^\circ = \sum (\Delta H_f^\circ \text{ of products}) - \sum (\Delta H_f^\circ \text{ of reactants})
\]
**Input the result:**
\[ \Delta H^\circ = \_\_\_\_ \text{ kJ} \]
**Interactions:**
- Users can submit their calculated answer by clicking on the "Submit Answer" button.
- There is an option to "Try Another Version" if needed.
- Note: Only 1 item attempt remaining.
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