The results shown below are mean productivity measurements (average number of assemblies completed per hour) for a random sample of workers at each of three plants. Research question: Are the mean hourly productivity levels the same for workers in these three plants? Hourly Productivity of Assemblers in Plants Plant Finished Units Produced per Hour A (9 workers) 3.6 5.1 2.8 4.6 4.7 4.1 3.4 2.9 4.5 B (6 workers) 2.7 3.1 5.0 1.9 2.2 3.2 C (10 workers) 6.8 2.5 5.4 6.7 4.6 3.9 5.4 4.9 7.1 8.4 Click here for the Excel Data File Fill in the missing data. (Round your p-value to 4 decimal places, mean values to 2 decimal places, and other answers to 3 decimal places.) Group Mean n Std. Dev Variance Plant A Plant B Plant C Total One-Factor ANOVA Source SS df MS F p-value Treatment Error Total Based on the hypotheses given below, choose the correct option. H0: μ1 = μ2 = μ3 H1: Not all the means are equal α = .05 Reject the null hypothesis if p-value < 0.05 Reject the null hypothesis if p-value > 0.05 We reject the null hypotheses. No Yes On the basis of the above findings, we conclude that one of the means is above and two are below the overall mean. all the means are above the overall mean. only one mean is above the overall mean. all the means are below the overall mean. Calculate the mean for each group and the Tukey test statistic Tcalc for each pair. Provide the critical values for both α = .05 and α = .01.(Input the mean values within the input boxes of the first row and input boxes of the first column. Input Tcalc in the appropriate boxes in the table. Round all answers to two decimal places.) Tukey simultaneous comparison t-values (d.f. = 22) Plant B Plant A Plant C Plant B Plant A Plant C Critical values for experimentwise error rate: 0.05 0.01 Based on the hypothesis given below, choose the correct option. H0: σ21 = σ22 = σ23 H1: Not all the variances are equal α = .05 Reject the null hypothesis if H < 6.94 Reject the null hypothesis if H > 6.94 Calculate the value of Hcalc. (Round your answer to 2 decimal places.) Hcalc On the basis of the above-determined Hcalc, we reject the null hypothesis. True False

The results shown below are mean productivity measurements (average number of assemblies completed per hour) for a random sample of workers at each of three plants. Research question: Are the mean hourly productivity levels the same for workers in these three plants? Hourly Productivity of Assemblers in Plants Plant Finished Units Produced per Hour A (9 workers) 3.6 5.1 2.8 4.6 4.7 4.1 3.4 2.9 4.5 B (6 workers) 2.7 3.1 5.0 1.9 2.2 3.2 C (10 workers) 6.8 2.5 5.4 6.7 4.6 3.9 5.4 4.9 7.1 8.4 Click here for the Excel Data File Fill in the missing data. (Round your p-value to 4 decimal places, mean values to 2 decimal places, and other answers to 3 decimal places.) Group Mean n Std. Dev Variance Plant A Plant B Plant C Total One-Factor ANOVA Source SS df MS F p-value Treatment Error Total Based on the hypotheses given below, choose the correct option. H0: μ1 = μ2 = μ3 H1: Not all the means are equal α = .05 Reject the null hypothesis if p-value < 0.05 Reject the null hypothesis if p-value > 0.05 We reject the null hypotheses. No Yes On the basis of the above findings, we conclude that one of the means is above and two are below the overall mean. all the means are above the overall mean. only one mean is above the overall mean. all the means are below the overall mean. Calculate the mean for each group and the Tukey test statistic Tcalc for each pair. Provide the critical values for both α = .05 and α = .01.(Input the mean values within the input boxes of the first row and input boxes of the first column. Input Tcalc in the appropriate boxes in the table. Round all answers to two decimal places.) Tukey simultaneous comparison t-values (d.f. = 22) Plant B Plant A Plant C Plant B Plant A Plant C Critical values for experimentwise error rate: 0.05 0.01 Based on the hypothesis given below, choose the correct option. H0: σ21 = σ22 = σ23 H1: Not all the variances are equal α = .05 Reject the null hypothesis if H < 6.94 Reject the null hypothesis if H > 6.94 Calculate the value of Hcalc. (Round your answer to 2 decimal places.) Hcalc On the basis of the above-determined Hcalc, we reject the null hypothesis. True False

Name: The results shown below are mean productivity measurements (average nu
Uploaded: 2024-03-20T07:06:16.000Z
Channel: Bartleby
Description: The results shown below are mean productivity measurements (average number of assemblies completed per hour) for a random sample of workers at each of three plants. Research question: Are the mean hourly productivity levels the same for workers in th

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

See similar textbooks

Related questions

Concept explainers

Topic Video

Question

The results shown below are mean productivity measurements (average number of assemblies completed per hour) for a random sample of workers at each of three plants. Research question: Are the mean hourly productivity levels the same for workers in these three plants?

Hourly Productivity of Assemblers in Plants
Plant	Finished Units Produced per Hour
A (9 workers)	3.6	5.1	2.8	4.6	4.7	4.1	3.4	2.9	4.5
B (6 workers)	2.7	3.1	5.0	1.9	2.2	3.2
C (10 workers)	6.8	2.5	5.4	6.7	4.6	3.9	5.4	4.9	7.1	8.4

Click here for the Excel Data File

Fill in the missing data. (Round your p-value to 4 decimal places, mean values to 2 decimal places, and other answers to 3 decimal places.)

Group	Mean	n	Std. Dev	Variance
Plant A
Plant B
Plant C
Total

One-Factor ANOVA
Source	SS	df	MS	F	p-value
Treatment
Error
Total

Based on the hypotheses given below, choose the correct option.

H₀: μ₁ = μ₂ = μ₃
H₁: Not all the means are equal

α = .05

Reject the null hypothesis if p-value < 0.05
Reject the null hypothesis if p-value > 0.05

We reject the null hypotheses.

On the basis of the above findings, we conclude that

one of the means is above and two are below the overall mean.
all the means are above the overall mean.
only one mean is above the overall mean.
all the means are below the overall mean.

Calculate the mean for each group and the Tukey test statistic T_calc for each pair. Provide the critical values for both α = .05 and α = .01.(Input the mean values within the input boxes of the first row and input boxes of the first column. Input T_calc in the appropriate boxes in the table. Round all answers to two decimal places.)

Tukey simultaneous comparison t-values (d.f. = 22)
	Plant B	Plant A	Plant C

Plant B
Plant A
Plant C
Critical values for experimentwise error rate:
	0.05
	0.01

Based on the hypothesis given below, choose the correct option.

H₀: σ²₁ = σ²₂ = σ²₃
H₁: Not all the variances are equal
α = .05

Reject the null hypothesis if H < 6.94
Reject the null hypothesis if H > 6.94

Calculate the value of H_calc. (Round your answer to 2 decimal places.)

H_calc

On the basis of the above-determined H_calc, we reject the null hypothesis.

True
False

Definition Definition Measure of central tendency that is the average of a given data set. The mean value is evaluated as the quotient of the sum of all observations by the sample size. The mean, in contrast to a median, is affected by extreme values. Very large or very small values can distract the mean from the center of the data. Arithmetic mean: The most common type of mean is the arithmetic mean. It is evaluated using the formula: μ = 1 N ∑ i = 1 N x i Other types of means are the geometric mean, logarithmic mean, and harmonic mean. Geometric mean: The nth root of the product of n observations from a data set is defined as the geometric mean of the set: G = x 1 x 2 ... x n n Logarithmic mean: The difference of the natural logarithms of the two numbers, divided by the difference between the numbers is the logarithmic mean of the two numbers. The logarithmic mean is used particularly in heat transfer and mass transfer. ln x 2 − ln x 1 x 2 − x 1 Harmonic mean: The inverse of the arithmetic mean of the inverses of all the numbers in a data set is the harmonic mean of the data. 1 1 x 1 + 1 x 2 + ...

Expert Solution

Trending now

This is a popular solution!

Step by step

Solved in 2 steps with 1 images

SEE SOLUTION Check out a sample Q&A here

Knowledge Booster

$Centre, Spread, and Shape of a Distribution$

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, statistics and related others by exploring similar questions and additional content below.