The resonant frequencies of the lowest frequency strings of a guitar are 82.4 Hz (E) and 110 Hz (A). Where would you depress the E string so that it had the same frequency as the next lowest string, the A at 110 Hz? 1st fret 2nd fret 3rd fret 4th fret 5th fret It is not possible to raise the frequency by shortening a string.
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The resonant frequencies of the lowest frequency strings of a guitar are 82.4 Hz (E) and 110 Hz (A). Where would you depress the E string so that it had the same frequency as the next lowest string, the A at 110 Hz?
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1st fret |
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2nd fret |
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3rd fret |
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4th fret |
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5th fret |
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It is not possible to raise the frequency by shortening a string. |
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- The C major musical scale has notes C D E F G A B C in order. Select the answers that apply. There are half steps between E and F and between B and C. There are no half steps. The frequencies are uniformly spaced. The scale spans a factor of 2 in frequency. Every note is separated from the one before it by a half step.13:35 O A O P A 1 99% A wave pulse travels down a slinky. The mass of the slinky is m = 0.89 kg and is initially stretched to a length L = 7.1 m. The wave pulse has an amplitude of A = 0.2 m and takes t = 0.426 s to travel down the stretched length of the slinky. The frequency of the wave pulse is f = 0.48 Hz. 1) What is the speed of the wave pulse? m/s Submit 2) What is the tension in the slinky? N Submit 3) What is the average speed of a piece of the slinky as a complete wave pulse passes? m/s Subrmit 4) What is the wavelength of the wave pulse? m Submit a 5) Now the slinky is stretched to twice its length (but the total mass does not change). What is the new tension in the slinky? (assume the slinky acts as a spring that obeys Hooke's Law) N Submit 6) What is the new mass density of the slinky? kg/m Subrmit " What is the new time it takes for a wave pulse to travel down the slinky? s Submit O 8) If the new wave pulse has the same frequency, what is the new wavelength? m Submit What…The lowest frequency string on a guitar is 65.5 cm long and is tuned to 80.0 Hz. By fingering the guitar at the fifth fret, you shorten the vibrating length of the string, thereby changing the fundamental frequency of this string to match that of the next-highest-frequency string on the guitar, 110 Hz. How long is the vibrating part of the lowest-frequency string when it is fingered at the fifth fret?
- Two identical guitar strings are prepared such that they have the same length (0.68) and are under the same amount of tension. The first string is plucked at one location, primarily exciting the first harmonic. The other string is plucked in a different location, primarily exciting the fourth harmonic. The resulting sounds give rise to a beat frequency of 324Hz. What is the wave propagation speed on the guitar strings? wave propagation speed: m/sOn a guitar, the lowest‑toned string is usually strung to the E note, which produces sound at 82.4 Hz. The diameter of E guitar strings is typically 0.0500 in, and the scale length between the bridge and nut (the effective length of the string) is 25.5 in. Various musical acts tune their E strings down to produce a "heavier" sound or to better fit the vocal range of the singer. As a guitarist you want to detune the E on your guitar to D (73.4 Hz). If you were to maintain the same tension in the string as with the E string, what diameter ?det of string would you need to purchase to produce the desired note? Assume all strings available to you are made of the same material.A guitar with strings of length L = 0.55 m has new strings put on it. The low E string has a linear density of ρ = 0.0062 kg/m and when tuned properly should produce a fundamental tone of ν = 82.41 Hz. L=0.55 m p= 0.0062 kg/m A: What is the proper tension the string should be under, in Newtons? B: If the string was mistakenly tuned to high E (ν = 330 Hz) what would the tension be, in Newtons?
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- World-renowned bluegrass musician, Frog Newton, has invited you to join his band. It is apparent that he is only looking for eye-candy on the stage, because you are only asked to play one note, the E at a frequency of 330 Hz. You make your own instrument using a string that is 1 meters long and has a mass of 3.5 grams. Now you need to calculate the necessary tension on the string, And you will be ready to jam! What is the tension needed to produce the E note?The resonant frequencies of the lowest frequency strings of a guitar are 82.4 Hz (E) and 110 Hz (A). Where would you depress the E string so that it had the same frequency as the next lowest string, the A at 110 Hz? 1st fret 2nd fret 3rd fret 4th fret 5th fret It is not possible to raise the frequency by shortening a string.