The resistors in the circuit below have the following values: R1 = 8.20 Ω, R2 = 7.00 Ω, and R3 = 4.40 Ω. The two batteries each have a voltage of 7.00 V. (a) Find the current in through R3. (b) How much power do the batteries deliver to R3?   I keep calculating the current incorrectly, yet I calculate the power.  Which uses the current.  Can you help me to  understand what part of Kirchhoff's Law I keep messing up.

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The resistors in the circuit below have the following values: R1 = 8.20 Ω, R2 = 7.00 Ω, and R3 = 4.40 Ω. The two batteries each have a voltage of 7.00 V.

(a) Find the current in through R3.

(b) How much power do the batteries deliver to R3?

 

I keep calculating the current incorrectly, yet I calculate the power.  Which uses the current.  Can you help me to  understand what part of Kirchhoff's Law I keep messing up. 

The diagram illustrates an electrical circuit with the following components:

1. **Resistors**:
   - \( R_1 \) is connected in series with the power source \( \varepsilon_1 \).
   - \( R_2 \) is connected in parallel to both \( R_1 \) and the power source \( \varepsilon_1 \).
   - \( R_3 \) is connected in series with the power source \( \varepsilon_2 \) and in parallel with \( R_2 \).

2. **Power Sources**:
   - \( \varepsilon_1 \) is a voltage source connected in series with \( R_1 \).
   - \( \varepsilon_2 \) is a voltage source connected in series with \( R_3 \).

The circuit features two parallel branches, each containing a resistor and a voltage source. The first branch contains \( R_1 \) in series with \( \varepsilon_1 \), while the second branch contains \( R_3 \) in series with \( \varepsilon_2 \). \( R_2 \) is positioned between these branches, in parallel to both sources and their respective loaded resistors. The circuit layout demonstrates a combination of series and parallel connections, highlighting various points for voltage and current analysis.
Transcribed Image Text:The diagram illustrates an electrical circuit with the following components: 1. **Resistors**: - \( R_1 \) is connected in series with the power source \( \varepsilon_1 \). - \( R_2 \) is connected in parallel to both \( R_1 \) and the power source \( \varepsilon_1 \). - \( R_3 \) is connected in series with the power source \( \varepsilon_2 \) and in parallel with \( R_2 \). 2. **Power Sources**: - \( \varepsilon_1 \) is a voltage source connected in series with \( R_1 \). - \( \varepsilon_2 \) is a voltage source connected in series with \( R_3 \). The circuit features two parallel branches, each containing a resistor and a voltage source. The first branch contains \( R_1 \) in series with \( \varepsilon_1 \), while the second branch contains \( R_3 \) in series with \( \varepsilon_2 \). \( R_2 \) is positioned between these branches, in parallel to both sources and their respective loaded resistors. The circuit layout demonstrates a combination of series and parallel connections, highlighting various points for voltage and current analysis.
The resistors in the circuit below have the following values: \( R_1 = 8.20 \, \Omega \), \( R_2 = 7.00 \, \Omega \), and \( R_3 = 4.40 \, \Omega \). The two batteries each have a voltage of \( 7.00 \, \text{V} \).

**Diagram Description:**

The circuit diagram includes three resistors \( R_1 \), \( R_2 \), and \( R_3 \). Resistors \( R_2 \) and \( R_3 \) are in parallel, and this combination is in series with \( R_1 \). There are two batteries labeled \( \varepsilon_1 \) and \( \varepsilon_2 \), each providing \( 7.00 \, \text{V} \).

**Questions:**
    
(a) Find the current in through \( R_3 \).

- Incorrect Attempt: 1.67 A 
- Additional Considerations: Is it possible to reduce the circuit by considering series and/or parallel combination of resistors? What is the total current delivered by the batteries? What is the voltage across \( R_3 \)?

(b) How much power do the batteries deliver to \( R_3 \)?

- Correct Answer: 2.64 W
Transcribed Image Text:The resistors in the circuit below have the following values: \( R_1 = 8.20 \, \Omega \), \( R_2 = 7.00 \, \Omega \), and \( R_3 = 4.40 \, \Omega \). The two batteries each have a voltage of \( 7.00 \, \text{V} \). **Diagram Description:** The circuit diagram includes three resistors \( R_1 \), \( R_2 \), and \( R_3 \). Resistors \( R_2 \) and \( R_3 \) are in parallel, and this combination is in series with \( R_1 \). There are two batteries labeled \( \varepsilon_1 \) and \( \varepsilon_2 \), each providing \( 7.00 \, \text{V} \). **Questions:** (a) Find the current in through \( R_3 \). - Incorrect Attempt: 1.67 A - Additional Considerations: Is it possible to reduce the circuit by considering series and/or parallel combination of resistors? What is the total current delivered by the batteries? What is the voltage across \( R_3 \)? (b) How much power do the batteries deliver to \( R_3 \)? - Correct Answer: 2.64 W
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