The researcher wants to examine the relationship between the stress level and grade point average of college students.StressGrade Point Average1101.01121.61181.21192.11222.61251.81302.0Sketch a scatter plot and comment on the correlation of the variablesIs the correlation statistically significant? Use a two-tailed test with α =.05Report your findings in APA format, 7th editionWhat percentage of variance for the grade point average is predicted from stressNOTE PLEASE USE THE FORMULA in the picture attached FOR QUESTION 2 and use the table to find the critical value Critical Values for the Pearson Correlation**To be sigailicant, the sample correlation, r, must be greater than or equal to the critical value in the table.Level of Significance forOne-Tailed Test.025.05.01.005Level of Significance forTwo-Tailed Testdf = n - 2.10.05.02.01.9995.980.934.988.997.99992.900.950.9903..805.878.959.729.669.811.882.917.754.8338746.622582.549.789.834.707.666.750.7167.798.7658.632.602.576.521.685.658.73510497.708.476.684.634.612.592.574.558.55312.458.532.66113.441.514497.482.641.623.606J4.4261541216468542.528.516.503492400.590.575.561.54953717.389.45618.378.444(9.369.360.4332042321482.526.352344.337.41322.404.472.462.515.505.496.48723.39624330.38845325.323.381.445.479.471.46345644926.374.367.361.355437.430.423.416.31727.311.306301.296282930.349.409.325.381.358.338.32235.275.418.393.37240.25730445.243.288.354.32550231.27360.211.250.29570.195.232.274302.183.173.164.256.283.26780.21790.205,24210.195.230.254Tuble VI of R. A. Fisher and F. Yates. Staristical Tables for Binlogical,Agricultural und Medical Research, Gh ed. London: Longman Group Ltd.,1974 (previously published by Oliver and Boyd Ltd., Edinburgh). CopyrightO1963 R. A. Fisher and F. Yates. Adapted and reprinted with permission ofPearson Education Limited, PEARSON CORRELATIONUse a two-tailed test with a =.05|FIRST PARTEx= Ey = Exy=Ex2 = Ey2 = N =ExEya ) SP -Σχy -b) SSy = Ey2 – Ey)²(Ex)2c) SSx = Ex2.SPd) r =(SSx)(SSy)SECOND PARTa. Let P be the true population correlation coefficientH0 =P =0a 0.05, df=n-2, Critical Value (refer the table )H1 = P #0b. T statistics = T Valuer - P1-r2V n - 2c. DecisionIf t value is less than critical value or more than critical value. H0 is rejected.Otherwise it Is fail to reject

Given : Data represents the stress level and grade point average of college students. (a) To find…

Answered: The researcher wants to examine the…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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The researcher wants to examine the relationship between the stress level and grade point average of college students.

Stress	Grade Point Average
110	1.0
112	1.6
118	1.2
119	2.1
122	2.6
125	1.8
130	2.0

Sketch a scatter plot and comment on the correlation of the variables
Is the correlation statistically significant? Use a two-tailed test with α =.05
Report your findings in APA format, 7th edition
What percentage of variance for the grade point average is predicted from stress

NOTE PLEASE USE THE FORMULA in the picture attached FOR QUESTION 2 and use the table to find the critical value

Critical Values for the Pearson Correlation*
*To be sigailicant, the sample correlation, r, must be greater than or equal to the critical value in the table.
Level of Significance for
One-Tailed Test
.025
.05
.01
.005
Level of Significance for
Two-Tailed Test
df = n - 2
.10
.05
.02
.01
.9995
.980
.934
.988
.997
.9999
2
.900
.950
.990
3.
.805
.878
.959
.729
.669
.811
.882
.917
.754
.833
874
6.
622
582
.549
.789
.834
.707
.666
.750
.716
7
.798
.765
8
.632
.602
.576
.521
.685
.658
.735
10
497
.708
.476
.684
.634
.612
.592
.574
.558
.553
12
.458
.532
.661
13
.441
.514
497
.482
.641
.623
.606
J4
.426
15
412
16
468
542
.528
.516
.503
492
400
.590
.575
.561
.549
537
17
.389
.456
18
.378
.444
(9
.369
.360
.433
20
423
21
482
.526
.352
344
.337
.413
22
.404
.472
.462
.515
.505
.496
.487
23
.396
24
330
.388
453
25
.323
.381
.445
.479
.471
.463
456
449
26
.374
.367
.361
.355
437
.430
.423
.416
.317
27
.311
.306
301
.296
28
29
30
.349
.409
.325
.381
.358
.338
.322
35
.275
.418
.393
.372
40
.257
304
45
.243
.288
.354
.325
50
231
.273
60
.211
.250
.295
70
.195
.232
.274
302
.183
.173
.164
.256
.283
.267
80
.217
90
.205
,242
10
.195
.230
.254
Tuble VI of R. A. Fisher and F. Yates. Staristical Tables for Binlogical,
Agricultural und Medical Research, Gh ed. London: Longman Group Ltd.,
1974 (previously published by Oliver and Boyd Ltd., Edinburgh). Copyright
O1963 R. A. Fisher and F. Yates. Adapted and reprinted with permission of
Pearson Education Limited,

PEARSON CORRELATION
Use a two-tailed test with a =.05|
FIRST PART
Ex= Ey = Exy=
Ex2 = Ey2 = N =
ExEy
a ) SP -Σχy -
b) SSy = Ey2 – Ey)²
(Ex)2
c) SSx = Ex2.
SP
d) r =
(SSx)(SSy)
SECOND PART
a. Let P be the true population correlation coefficient
H0 =P =0
a 0.05, df=n-2, Critical Value (refer the table )
H1 = P #0
b. T statistics = T Value
r - P
1-r2
V n - 2
c. Decision
If t value is less than critical value or more than critical value. H0 is rejected.
Otherwise it Is fail to reject

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