Answered: The research hypothesis posits that the…

The research hypothesis posits that the treatment association between two variables will be greater than zero (H1: rxy > 0). What would be concluded for r(29) = .267, p > .05?

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

See similar textbooks

Similar questions

You run a regression analysis on a bivariate set of data (n=39). With ¯x=24.8 and ¯y=43.4 you obtain the regression. equation y=2.058x−27.113 with a correlation coefficient of r=0.251. You want to predict what value (on average) for the response variable will be obtained from a value of 180 as the explanatory variable.What is the predicted response value?y = (Report answer accurate to one decimal place.)
The result for a Pearson’s r between students’ test scores and their motivation was, r(24) = .32, p = .07. What can the researcher conclude? Group of answer choices There is no statistical significant relationship between students’ motivation and their test scores. As students’ motivation increased, their test scores decreased. There is a negative relationship between the variables.
You run a regression analysis on a bivariate set of data (n=49n=49). You obtain the regression equation y=1.371x−2.629 with a correlation coefficient of r=0.664 (which is significant at α=0.01. You want to predict what value (on average) for the explanatory variable will give you a value of 50 on the response variable.What is the predicted explanatory value?x =
You run a regression analysis on a bivariate set of data (n = 110). You obtain the regression equation y = – 3.546x 4.393 0.248 (which is significant at a = 0.01). You want to predict with a correlation coefficient of r = - what value (on average) for the explanatory variable will give you a value of 100 on the response variable. What is the predicted explanatory value? X = (Report answer accurate to one decimal place.)
You run a regression analysis on a bivariate set of data (n=32). With ¯x=22.4 and y¯=65.8, you obtain the regression equation y=−3.812x+52.761 with a correlation coefficient of r=−0.137 You want to predict what value (on average) for the response variable will be obtained from a value of 70 as the explanatory variable.What is the predicted response value? y = (Report answer accurate to one decimal place.)
You may need to use the appropriate technology to answer this question. A regression analysis involving 45 observations relating a dependent variable and two independent variables resulted in the following information. ŷ = 0.406 + 1.3385x₁ + 2x₂ The SSE for the above model is 43. When two other independent variables were added to the model, the following information was provided. ŷ = 1.9 - 3x₁ + 12x2 + 4x3 + 8x4 This model's SSE is 36. At a 0.05 level of significance, test to determine if the two added independent variables contribute significantly to the model. State the relevant null and alternative hypotheses. O Ho: One or more of the parameters is not equal to zero. H₂: B₁ = P₂ = P3 =B4 = 0 B1 O Ho: One or more of the parameters is not equal to zero. H₂: B3 =B₁ = 0 O Ho: B3 = P4 = 0 H₂: None of the parameters are equal to zero. O Ho: B3 B4= = = H₂: One or more of the parameters is not equal to zero. O Ho: P₁ = P₂ = P3= P4= H: One or more of the parameters is not equal to zero. Find…
You run a regression analysis on a bivariate set of data (n = 52). With a = 52.2 and j = 24.1, you obtain the regression equation 1.305x – 47.088 with a correlation coefficient of r = - 0.988. You want to predict what value (on average) for the response variable will be obtained from a value of 170 as the explanatory variable. What is the predicted response value?
Urjant need answer
You are a researcher who wants to know what the mean (µ) level of anxiety would be for the whole population if they were all receiving a new anti-anxiety therapy. You can’t give the therapy to the whole population, so you give it to a sample, and you get M = 32.1 as the average anxiety level for the sample on the therapy. What is the reason that you can’t just simply assume that µ = 32.1? You didn’t use random assignment Sampling error Descriptive statistics Inferential statistics
A researcher would like to examine how the chemical tryptophan, contained in foods such as turkey, can affect mental alertness. A sample of n = 9 college students is obtained and each student’s performance on a familiar video game is measured before and after eating a traditional Thanksgiving dinner including roast turkey. The average score dropped by M = 14 points after the meal with SS = 1152 for the difference scores. A. Is there is significant difference in performance before eating versus after eating? Use a two-tailed test with α = .05. SMD = ___________________________ tcritical = ________________________ tcalculated = ________________________ Decision = _______________________ B. Compute r2 to measure the size of the effect. r2 = _____________________________ C. Write a sentence demonstrating how the outcome of the test and the measure of effect size would…
You run a regression analysis on a bivariate set of data (n=32). You obtain the regression equation y=4.224x+-61.908 with a correlation coefficient of r=0.74 (which is significant at α=0.01). You want to predict what value (on average) for the explanatory variable will give you a value of 20 on the response variable. What is the predicted explanatory value? x =
You run a regression analysis on a bivariate set of data (n = 74). You obtain the regression equation y=1.792x+ −17.683 with a correlation coefficient of r=0.793 (which is significant at α=0.01. You want to predict what value (on average) for the explanatory variable will give you a value of 50 on the response variable. What is the predicted explanatory value? x =