The regression equation is y=_____+____x. ​(Round to one decimal place as​ needed.)   2.The best predicted weight for an overhead width of 2 cm is _____ kg. ​(Round to one decimal place as​ needed.)   3. Can the prediction be​ correct? What is wrong with predicting the weight in this​ case?   A.The prediction cannot be correct because a negative weight does not make sense and because there is not sufficient evidence of a linear correlation.   B.The prediction cannot be correct because a negative weight does not make sense. The width in this case is beyond the scope of the available sample data.   C.The prediction cannot be correct because there is not sufficient evidence of a linear correlation. The width in this case is beyond the scope of the available sample data.   D.The prediction can be correct. There is nothing wrong with predicting the weight in this case.

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help with questions 1, 2 and 3 please ...
 
1. The regression equation is y=_____+____x.
​(Round to one decimal place as​ needed.)
 
2.The best predicted weight for an overhead width of 2 cm is _____ kg.
​(Round to one decimal place as​ needed.)
 
3. Can the prediction be​ correct? What is wrong with predicting the weight in this​ case?
 
A.The prediction cannot be correct because a negative weight does not make sense and because there is not sufficient evidence of a linear correlation.
 
B.The prediction cannot be correct because a negative weight does not make sense. The width in this case is beyond the scope of the available sample data.
 
C.The prediction cannot be correct because there is not sufficient evidence of a linear correlation. The width in this case is beyond the scope of the available sample data.
 
D.The prediction can be correct. There is nothing wrong with predicting the weight in this case.
Find the regression equation, letting overhead width be the predictor (x) variable. Find the best predicted weight
of a seal if the overhead width measured from a photograph is 2 cm. Can the prediction be correct? What is
wrong with predicting the weight in this case? Use a significance level of 0.05.
Overhead Width (cm)
Weight (kg)
7.8
7.5
8.6
9.3
8.1
7.7
153
171
211
213
185
174
Click the icon to view the critical values of the Pearson correlation coefficient r.
The regression equation is y =D+x.
(Round to one decimal place as needed.)
Transcribed Image Text:Find the regression equation, letting overhead width be the predictor (x) variable. Find the best predicted weight of a seal if the overhead width measured from a photograph is 2 cm. Can the prediction be correct? What is wrong with predicting the weight in this case? Use a significance level of 0.05. Overhead Width (cm) Weight (kg) 7.8 7.5 8.6 9.3 8.1 7.7 153 171 211 213 185 174 Click the icon to view the critical values of the Pearson correlation coefficient r. The regression equation is y =D+x. (Round to one decimal place as needed.)
Expert Solution
Step 1

The following is the given Data :

Overhead Width = x Weight = y
7.8 153
7.5 171
8.6 211
9.3 213
8.1 185
7.7 174

The independent variable is xx, and the dependent variable is yy. In order to compute the regression coefficients, the following table needs to be used:

  x y x*y x2 y2
  7.8 153 1193.4 60.84 23409
  7.5 171 1282.5 56.25 29241
  8.6 211 1814.6 73.96 44521
  9.3 213 1980.9 86.49 45369
  8.1 185 1498.5 65.61 34225
  7.7 174 1339.8 59.29 30276
Sum = 49 1107 9109.7 402.44 207041

 

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