The region D above lies between the graphs of 1 y = −3 − (x + 4)² and y = −7+ (x +6)³. It can be described in two ways. 1. If we visualize the region having "top" and "bottom" boundaries, express each as functions of a and provide the interval of x-values that covers the entire region. "top" boundary g2(x) = "bottom" boundary 9₁(x): = interval of a values that covers the region = 2. If we visualize the region having "right" and "left" boundaries, then the "right" boundary must be defined piece-wise. Express each as functions of y for the

Glencoe Algebra 1, Student Edition, 9780079039897, 0079039898, 2018
18th Edition
ISBN:9780079039897
Author:Carter
Publisher:Carter
Chapter1: Expressions And Functions
Section1.8: Interpreting Graphs Of Functions
Problem 1GP
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D
The region D above lies between the graphs of
1
y = -3- (x+4)² and y = -7 + (x+6)³. It can
9
be described in two ways.
1. If we visualize the region having "top" and "bottom"
boundaries, express each as functions of x and provide
the interval of x-values that covers the entire region.
"top" boundary g₂ (x)
=
"bottom" boundary 9₁(x) =
=
interval of a values that covers the region =
2. If we visualize the region having "right" and "left"
boundaries, then the "right" boundary must be defined
piece-wise. Express each as functions of y for the
provided intervals of y-values that covers the entire
region.
For 4 ≤ y ≤-3 the "right" boundary as a piece-wise
function f2(y) =
For -7 < y < -4 the "right" boundary f2(y) =
For -7 < y <-3 the "left" boundary f₁(y) =
Transcribed Image Text:D The region D above lies between the graphs of 1 y = -3- (x+4)² and y = -7 + (x+6)³. It can 9 be described in two ways. 1. If we visualize the region having "top" and "bottom" boundaries, express each as functions of x and provide the interval of x-values that covers the entire region. "top" boundary g₂ (x) = "bottom" boundary 9₁(x) = = interval of a values that covers the region = 2. If we visualize the region having "right" and "left" boundaries, then the "right" boundary must be defined piece-wise. Express each as functions of y for the provided intervals of y-values that covers the entire region. For 4 ≤ y ≤-3 the "right" boundary as a piece-wise function f2(y) = For -7 < y < -4 the "right" boundary f2(y) = For -7 < y <-3 the "left" boundary f₁(y) =
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