The red blood cell counts​ (in millions of cells per​ microliter) for a population of adult males can be approximated by a normal​ distribution, with a mean of 5.4 million cells per microliter and a standard deviation of 0.5 million cells per microliter. (a) What is the minimum red blood cell count that can be in the top 23​% of​ counts? (b) What is the maximum red blood cell count that can be in the bottom 10​% of​ counts?

Q: The annual per capita consumption of oranges (in pounds) in the United States  can be approximated…

A: It is given that the mean and standard deviation are 19.2 and 4, respectively.

Q: The percent of fat calories that a person consumes each day is normally distributed with a mean of…

A: Solution: Let X be the average percent of fat calories. From the given information, X follows normal…

Q: Measuring lung function: One of the measurements used to determine the health of a person's lungs is…

A: The hypothesized mean is 2.1.

Q: Scores by women on the SAT-1 test are normally distributed with a mean of 988 and a standard…

A: Given Information Now we have to calculate corresponding Z value                         Z = 0.7388…

Q: Please help him by finding the standard error of the mean for these data.

A: To find the standard error of the mean.Given that,

Q: Assume that the amount of time a person experiences cold virus symptoms are normally distributed…

A: Given data Mean = 7.5 days  Standard deviation  = 1.5d days To find: What proportion of cold…

Q: The serum cholesterol level in men aged 18 to 74 are normally distributed with a mean of 178.1 and a…

A:

Q: Approximately what percentage of normally distributed data will fall within 2 standard deviations…

A: Based on the Concept of Empirical Rule: About 68% of the area under the curve falls within 1…

Q: Suppose that the antenna lengths of woodlice are approximately normally distributed with a mean of…

A: We have given that.   X~N( μ , ?^2 )   μ =0.25 , ? =0.05   Z-score =( x - μ )/?

Q: If the mean exam score of a class was 75%, with a standard deviation of 15%,what percent of students…

A: Given,mean(μ)=0.75standard deviation(σ)=0.15

Q: The SAT scores (X) of the students in the U.S. in 2011 are normally distributed with a mean 1500 and…

A: The objective of this question is to find the percentage of students who scored below Darth Vader on…

Q: The scores on a standardized test are normally distributed with a mean of 90 and standard deviation…

A:

Q: The heights of women in a particular community are normally distributed with a mean of 65 inches and…

A: We have to find given proportion..

Q: A normal distribution of scores representing ones fear of crime is analyzed.  Higher scores indicate…

A: The question is about normal distribution.Given :Population mean score (  ) = 6Population standard…

Q: It has been reported that the standard deviation of the speeds of drivers on interstate -35 near…

A: It has been reported that the standard deviation of the speeds of drivers is 6.8 miles per hour for…

Q: The scores on a standardized test are normally distributed with a mean of 105 and standard deviation…

A: Let k is 0.6 standard deviation below the mean.  That means -0.6 is the z score of the value.…

Q: For a random sample of  70  overweight men, the mean of the number of pounds that they were…

A: given data  n = 70 x¯ = 28 poundsσ = 3.8 poundsbest point estimate for population mean  = ?

Q: 2000 freshmen at state university took a biology test. the scores were normally distributed with a…

A: Solution: Let X be the scores. From the given information, X follows normal distribution with mean…

Q: An instructor in a large lecture class found, at the end of the semester, that the total point…

A: The provided information is:

Q: The time needed to take an exam is normally distributed with an average of 120 minutes and a…

A: Given,mean(μ)=120standard devition(σ)=20

Q: The scores on a standardized test are normally distributed with a mean of 90 and standard deviation…

A: The test score is 0.6 standard deviations above the mean is obtained below: From the given…

Q: Glucose levels in patie tz free of diabetes are assumed to follow a normal distribution with a mean…

A: Here, mean is 120 and standard deviation is 16.

Q: The scores of a standarlized test form a normal distribution with a mean of 300 and standard…

A: The Z-score of a random variable X is defined as follows: Z = (X – µ)/σ. Here, µ and σ are the mean…

Q: LED lamp has a mean usage of 750 hours with standard deviation of 50 hours. If LED lamp usage is…

A: Provided information is,  A LED lamp has a mean usage of 750 hours with standard deviation of 50…

Q: The mean value of land and buildings per acre from a sample of farms is ​$1800​, with a standard…

A: Solution: Let X be the value of land and buildings per acre. From the given information, X follows…

Q: The scores on the final exam in a statistics course are close to being normally distributed. The…

A: Normal distribution: It is a continuous probability distribution, that is bell-shaped with lighter…

Q: Assume that an intelligence test scores are distributed normallt with a mean of 100 and a standard…

A: Standard normal distribution: The standard normal distribution is a special case of normal…

Q: Suppose that the blood pressure of the human inhabitants of a certain Pacific island is distributed…

A:

Q: Suppose the distribution of typing speeds in words per minute for experienced typists can be…

A:

Q: he scores on a standardized test are normally distributed with a mean of 120 and standard deviation…

A:

Q: score of x=14, which value for the standard deviation would give this person the highest position in…

A: We have given that µ = 52 x = 14 z-score formula is given as  z =( x - μ )/σ

Q: The annual per capita consumption of oranges (in pounds) in the United States  can be approximated…

A: It is given that the mean and standard deviation are 19.2 and 4, respectively.

Estimation

A new framework of data analysis where the new statistical methods are used for interpreting the results and analyzing the data is known as estimation in statistics.