The recurrence relation is given as: an = 04 an-1 - 4 an-2 The initial conditions are given as: ao =1, a¡ =4 and az = 12, . %3D When you solve the general equation, the constants alpha 1 and alpha 2 are respectively calculated as: Use a calculator and calculate ag When you solve the characteristic equation, the root/roots of the characteristic equation can be found as:
The recurrence relation is given as: an = 04 an-1 - 4 an-2 The initial conditions are given as: ao =1, a¡ =4 and az = 12, . %3D When you solve the general equation, the constants alpha 1 and alpha 2 are respectively calculated as: Use a calculator and calculate ag When you solve the characteristic equation, the root/roots of the characteristic equation can be found as:
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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![The recurrence relation is given as: an = 04 an-1 - 4 an-2
The initial conditions are given as: a, =1, a, =4 and az = 12, .
When you solve the general equation, the constants alpha 1 and alpha 2 are respectively calculated as:
Seç.
Seç.
Use a calculator and calculate ag
1 and 1
-2 and 1
16368
-2
When you solve the characteristic equation, the root/roots of the characteristic equation can be found as:
-0.5 and 2
12464
11264
2
2 and -2](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F12e2d6a2-46ae-4143-aab2-93e15aa8b62e%2F0bad2ebf-a3e1-49c0-be79-d4ca4757ea3d%2F1wzt5t_processed.png&w=3840&q=75)
Transcribed Image Text:The recurrence relation is given as: an = 04 an-1 - 4 an-2
The initial conditions are given as: a, =1, a, =4 and az = 12, .
When you solve the general equation, the constants alpha 1 and alpha 2 are respectively calculated as:
Seç.
Seç.
Use a calculator and calculate ag
1 and 1
-2 and 1
16368
-2
When you solve the characteristic equation, the root/roots of the characteristic equation can be found as:
-0.5 and 2
12464
11264
2
2 and -2
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