The recurrence relation is given as: an = 04 an-1 - 4 an-2The initial conditions are given as: a, =1, a, =4 and az = 12, .When you solve the general equation, the constants alpha 1 and alpha 2 are respectively calculated as:Seç.Seç.Use a calculator and calculate ag1 and 1-2 and 116368-2When you solve the characteristic equation, the root/roots of the characteristic equation can be found as:-0.5 and 2124641126422 and -2

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The recurrence relation is given as: an = 04 an-1 - 4 an-2 The initial conditions are given as: ao =1, a¡ =4 and az = 12, . %3D When you solve the general equation, the constants alpha 1 and alpha 2 are respectively calculated as: Use a calculator and calculate ag When you solve the characteristic equation, the root/roots of the characteristic equation can be found as:

The recurrence relation is given as: an = 04 an-1 - 4 an-2 The initial conditions are given as: ao =1, a¡ =4 and az = 12, . %3D When you solve the general equation, the constants alpha 1 and alpha 2 are respectively calculated as: Use a calculator and calculate ag When you solve the characteristic equation, the root/roots of the characteristic equation can be found as:

Advanced Engineering Mathematics

10th Edition

ISBN:9780470458365

Author:Erwin Kreyszig

Publisher:Erwin Kreyszig

Chapter2: Second-order Linear Odes

Section: Chapter Questions

Problem 1RQ

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Question

The recurrence relation is given as: an = 04 an-1 - 4 an-2
The initial conditions are given as: a, =1, a, =4 and az = 12, .
When you solve the general equation, the constants alpha 1 and alpha 2 are respectively calculated as:
Seç.
Seç.
Use a calculator and calculate ag
1 and 1
-2 and 1
16368
-2
When you solve the characteristic equation, the root/roots of the characteristic equation can be found as:
-0.5 and 2
12464
11264
2
2 and -2

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