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The recurrence relation an-an-1+3 with the initial condition ao = 1 Multiple Choice The solution for the recurrence relation is an=3+an-1=3+3+an-2=2-3+an-2-3-3+an-3 =- =n-3+ an-n=n-3+ ao=3n+1 The solution for the recurrence relation is an = 3+an-1= 32+an-2=3³+ an-3 3+ an-n=3+ a0=3"+1 The solution for the recurrence relation is an = 3+ an-1=3+an-2=3+an-2=3+an-3==3+ an- n=3+ ap=3+1=4 The solution for the recurrence relation is an = 3 + an-1-3-3+an-2-an-2-an-31 an-n=0=1

The recurrence relation an-an-1+3 with the initial condition ao = 1 Multiple Choice The solution for the recurrence relation is an=3+an-1=3+3+an-2=2-3+an-2-3-3+an-3 =- =n-3+ an-n=n-3+ ao=3n+1 The solution for the recurrence relation is an = 3+an-1= 32+an-2=3³+ an-3 3+ an-n=3+ a0=3"+1 The solution for the recurrence relation is an = 3+ an-1=3+an-2=3+an-2=3+an-3==3+ an- n=3+ ap=3+1=4 The solution for the recurrence relation is an = 3 + an-1-3-3+an-2-an-2-an-31 an-n=0=1

Trigonometry (11th Edition)
Trigonometry (11th Edition)
11th Edition
ISBN:9780134217437
Author:Margaret L. Lial, John Hornsby, David I. Schneider, Callie Daniels
Publisher:Margaret L. Lial, John Hornsby, David I. Schneider, Callie Daniels
Chapter1: Trigonometric Functions
Section: Chapter Questions
Problem 1RE: 1. Give the measures of the complement and the supplement of an angle measuring 35°.
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Ch 02 Sec 4 Ex 16 (b) - Iterative Method The recurrence relation an = an -1 +3 with the initial condition ao = 1 Multiple Choice O O The solution for the recurrence relation is an = 3+ an-1= 3+3+an-2=2·3+an-2 = 3·3+an-3=- =n-3+ an-n=n-3+ ao=3n+1 The solution for the recurrence relation is an=3+ an-1= 3²+ an-2= 3³ + an-3 = 3 + an-n=3"+ ao=3"+1 The solution for the recurrence relation is an = 3+an-1=3+ an-2=3+an-2=3+ an-3 The solution for the recurrence relation is an=3+ an-1-3-3+an-2= @n-2=an-3 -=3+ an-n² n=3+ ao=3+1=4 -an-nao=1
Transcribed Image Text:Ch 02 Sec 4 Ex 16 (b) - Iterative Method The recurrence relation an = an -1 +3 with the initial condition ao = 1 Multiple Choice O O The solution for the recurrence relation is an = 3+ an-1= 3+3+an-2=2·3+an-2 = 3·3+an-3=- =n-3+ an-n=n-3+ ao=3n+1 The solution for the recurrence relation is an=3+ an-1= 3²+ an-2= 3³ + an-3 = 3 + an-n=3"+ ao=3"+1 The solution for the recurrence relation is an = 3+an-1=3+ an-2=3+an-2=3+ an-3 The solution for the recurrence relation is an=3+ an-1-3-3+an-2= @n-2=an-3 -=3+ an-n² n=3+ ao=3+1=4 -an-nao=1
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