The ready list RL contains processes 2 then 3. Consider (1), (2) as independent operations. РСВ З РСВО PCB 1 РСВ 2 process_state blocked blocked running ready -2 other_resources ... ... RCB 0 RCB 1 RCB 2 RCB 3 state free allocated allocated allocated waiting_list 1 (1) Process 2 requests resource 0. After the operation: Process 2 is Select v Resource O's waiting list Select Resource O is Select RL contains the processes Ex: 1, 2, 3 (2) Process 2 requests resource 3. After the operation: Process 2 is Select v Resource 3's waiting list Select Resource 3 is Select RL contains the processes Ex: 1, 2, 3

The ready list RL contains processes 2 then 3. Consider (1), (2) as independent operations. РСВ З РСВО PCB 1 РСВ 2 process_state blocked blocked running ready -2 other_resources ... ... RCB 0 RCB 1 RCB 2 RCB 3 state free allocated allocated allocated waiting_list 1 (1) Process 2 requests resource 0. After the operation: Process 2 is Select v Resource O's waiting list Select Resource O is Select RL contains the processes Ex: 1, 2, 3 (2) Process 2 requests resource 3. After the operation: Process 2 is Select v Resource 3's waiting list Select Resource 3 is Select RL contains the processes Ex: 1, 2, 3

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

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Q1: a) Can a process transition from waiting for an 1/0 operation to the terminated state? Why or why not? b) Round-robin schedulers normally maintain a list of all runnable processes, with each process occurring exactly once in the list. What would happen if a process occurred twice in the list? Can you think of any reason for allowing this?
Assume that there are the following processes in the deadline scheduler queue: Process Arrival Runtime Period Deadline 1 0 2 12 10 2 2 4 20 16 3 4 3 15 14 Complete the following schedule so each of the processes adheres to the deadline policy by replacing a dot with a process number (as necessary): TIME: 01234567890123456789012345678901234567890123456789 PROCESS: 112222333.......................................
1. Two processes, A and B, each need three resources, 1, 2, and 3. Suppose 4 requests them in the order 1, 2, 3. If B also requests them in the same order, deadlock is not possible. However, if B requests them in the order 3, 2, 1, then deadlock is possible. With three resources, there are 3! or six possible orders in which B can request them. For each possible order in which B can request these resources, state whether or not a deadlock is possible for that order. (Assume that once a process acquires a resource, it does not release that resource until the end of that process.) a) 1, 2, 3 b) 1,3,2 c) 2, 1, 3 d) 2, 3, 1 e) 3, 1, 2 f) 3, 2, 1
A deadlock occurs when a group of processes is stalled because one process is holding a resource and waiting for another process to obtain it. Consider the situation when two trains are approaching each other on the same track and there is only one track: once they are in front of each other, neither train can proceed. In operating systems, a similar scenario happens when two or more processes possess certain resources while waiting on resources owned by other processes (s). In the picture below, Process 1 is holding Resource 1 and waiting for Process 2 to acquire Resource 2, while Process 2 is waiting for Resource 1. Give an example of a realistic deadlock avoidance approach and describe the basic strategy behind it.
you are tasked with analyzing an algorithm which schedulea processes in a multiprogramming system. You are working with a computer that has two CPUs, each CPU having two threads (hyperthreading). You are studying a scenario with three processes: P0, P1, & P2., with run times of 5, 10, & 20 msecs, respectively. All 3 programs are 100% CPU bound, don't block, and always run in the CPU it's assigned to. How long will it take for these programs to complete execution. Show three different possible outcomes (and assigned process to processor, 3 different combinations and resulting total time for all three to complete)
Consider the following code snippet: waitpid(-1, &status, 0); Which of the following correctly describes the purpose of this code snippet? it is equivalent to wait(&status); it causes the parent process to wait for the child process that terminates first and fetch that child's termination status it causes the parent process to wait for the child process whose pid is -1 and fetch that child's termination status The first two choices are both correct None of the above choices are correct Which of the following statements about wait(2) and waitpid(2) are true? The waitpid(2) function can block the caller until a child process terminates, whereas wait(2) has an option that prevents it from blocking. The wait(2) function doesn't wait for the child that terminates first; it has a number of options that control which process it waits for. If a child has already terminated and is a zombie, wait(2) returns immediately with that child's status. Otherwise, it blocks the caller until a child…
2. a) Your colleague has invented a new scheduling algorithm using the multilevel queue approach. This list of processes showing CPU burst times is below. There are three queues used in the application. The processes all start on the first queue and receive upto 10ms of burst time. Once the process has received the 10ms on the first queue, if the process still requires burst time it is passed to the second queue where it receives upto 20ms. Once the process has received the 20ms on the second queue, if the process still requires burst time it is passed to the third queue where it receives CPU time until it is completed. The operating system will only start allocating CPU time to processes on the second queue when queue 1 is empty. The operating system will only start allocating CPU time to processes on the third queue when queue 2 is empty. Process Number P1 P2 P3 P4 Burst time (ms) 21 8 35 50 i) Does this algorithm give higher priority to any queue over the others and any processes…
Description:The project I am working on needs to demonstrate how two processes (parent and child) can communicatethrough a shared memory region, with the child process writing a value to the shared memoryand the parent process reading that value. This is my code and I wont run. Can you help: #include <stdio.h>#include <stdlib.h>#include <sys/types.h>#include <sys/ipc.h>#include <sys/shm.h>#include <unistd.h> #define SHM_SIZE 1024 /* shared memory size */ void error_exit(const char *msg) { perror(msg); exit(EXIT_FAILURE);} int main() { key_t key; int shmid; char *data; // Create a unique key for shared memory if ((key = ftok("shared_memory.c", 'R')) == -1) { error_exit("ftok"); } // Create the shared memory segment if ((shmid = shmget(key, SHM_SIZE, 0644 | IPC_CREAT)) == -1) { error_exit("shmget"); } // Attach the shared memory segment to our data space data = shmat(shmid, (void *)0, 0); if…
assume a system has 6 identical resources and N processes competing for them. each process can request at most 2 resources. what is the maximum value of N for the system to be deadlock free?
Which of the following are true with respect to a mutiprogrammed, time-shared (multi-tasking) environments? (Select all that apply.) Context-switching provides optimal use of the CPU by scheduling ready processes as soon as the CPU is available. Context switching is a zero cost operation. There is better performance when the multiprogramming level is very low. Critical sections and race conditions are a direct result of context switching and programs sharing memory.
Bounded waiting requires that \A bound must exist on the number of times that other processes are allowed to enter their critical sections a) true b) false
Do the Round Robin:Quantom=3 scheduling algorithm to the list of processes. The process should provide : a. A detailed gantt chart b. finish time, turnaround time, waiting time c. The average turnaround time d. The average waiting time