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The reading speed of second grade students in a large city is approximately normal, with a mean of 88 words per minute (wpm) and a standard deviation of 10 wpm. Complete parts (a) through (f). Click here to view the standard normal distribution table (page 1), Click here to view the standard normal distribution table (page 2). (e) A teacher instituted a new reading program at school. After 10 weeks in the program, Select the correct choice below and fill in the answer boxes within your choice. (Type integers or decimals rounded to four decimal places as needed.) was found that the mean reading speed of a random sample of 21 second grade students was 90.8 wpm. What might you conclude based on this result? A. A mean reading rate of 90.8 wpm is unusual since the probability of obtaining a result of 90.8 wpm or more is This means that we would expect a mean reading rate of 90.8 or higher from a population whose mean reading rate is 88 in of every 100 random samples of size n=21 students. The new program is abundantly more effective than the old program. B. A mean reading rate of 90.8 wpm is not unusual since the probability of obtaining a result of 90.8 wpm or more is 0.1003. This means that we would expect a mean reading rate of 90.8 or higher from a population whose mean reading rate is 88 in 10 of every 100 random samples of size n=21 students. The new program is not abundantly more effective than the old program. (f) There is a 5% chance that the mean reading speed of a random sample of 22 second grade students willl exceed what value? There is a 5% chance that the mean reading speed of a random sample of 22 second grade students will exceed wpm. (Round to two decimal places as needed.)

The reading speed of second grade students in a large city is approximately normal, with a mean of 88 words per minute (wpm) and a standard deviation of 10 wpm. Complete parts (a) through (f). Click here to view the standard normal distribution table (page 1), Click here to view the standard normal distribution table (page 2). (e) A teacher instituted a new reading program at school. After 10 weeks in the program, Select the correct choice below and fill in the answer boxes within your choice. (Type integers or decimals rounded to four decimal places as needed.) was found that the mean reading speed of a random sample of 21 second grade students was 90.8 wpm. What might you conclude based on this result? A. A mean reading rate of 90.8 wpm is unusual since the probability of obtaining a result of 90.8 wpm or more is This means that we would expect a mean reading rate of 90.8 or higher from a population whose mean reading rate is 88 in of every 100 random samples of size n=21 students. The new program is abundantly more effective than the old program. B. A mean reading rate of 90.8 wpm is not unusual since the probability of obtaining a result of 90.8 wpm or more is 0.1003. This means that we would expect a mean reading rate of 90.8 or higher from a population whose mean reading rate is 88 in 10 of every 100 random samples of size n=21 students. The new program is not abundantly more effective than the old program. (f) There is a 5% chance that the mean reading speed of a random sample of 22 second grade students willl exceed what value? There is a 5% chance that the mean reading speed of a random sample of 22 second grade students will exceed wpm. (Round to two decimal places as needed.)

MATLAB: An Introduction with Applications
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
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The reading speed of second grade students in a large city is approximately normal, with a mean of 88 words per minute (wpm) and a standard deviation of 10 wpm. Complete parts (a) through (f). Click here to view the standard normal distribution table (page 1). Click here to view the standard normal distribution table (page 2). (e) A teacher instituted a new reading program at school. After 10 weeks in the program, it was found that the mean reading speed of a random sample of 21 second grade students was 90.8 wpm. What might you conclude based on this result? Select the correct choice below and fill in the answer boxes within your choice. (Type integers or decimals rounded to four decimal places as needed.) A. A mean reading rate of 90.8 wpm is unusual since the probability of obtaining a result of 90.8 wpm or more is _____. This means that we would expect a mean reading rate of 90.8 or higher from a population whose mean reading rate is 88 in _____ of every 100 random samples of size n = 21 students. The new program is abundantly more effective than the old program. B. A mean reading rate of 90.8 wpm is not unusual since the probability of obtaining a result of 90.8 wpm or more is 0.1003. This means that we would expect a mean reading rate of 90.8 or higher from a population whose mean reading rate is 88 in 10 of every 100 random samples of size n = 21 students. The new program is not abundantly more effective than the old program. (f) There is a 5% chance that the mean reading speed of a random sample of 22 second grade students will exceed what value? There is a 5% chance that the mean reading speed of a random sample of 22 second grade students will exceed _____ wpm. (Round to two decimal places as needed.)
Transcribed Image Text:The reading speed of second grade students in a large city is approximately normal, with a mean of 88 words per minute (wpm) and a standard deviation of 10 wpm. Complete parts (a) through (f). Click here to view the standard normal distribution table (page 1). Click here to view the standard normal distribution table (page 2). (e) A teacher instituted a new reading program at school. After 10 weeks in the program, it was found that the mean reading speed of a random sample of 21 second grade students was 90.8 wpm. What might you conclude based on this result? Select the correct choice below and fill in the answer boxes within your choice. (Type integers or decimals rounded to four decimal places as needed.) A. A mean reading rate of 90.8 wpm is unusual since the probability of obtaining a result of 90.8 wpm or more is _____. This means that we would expect a mean reading rate of 90.8 or higher from a population whose mean reading rate is 88 in _____ of every 100 random samples of size n = 21 students. The new program is abundantly more effective than the old program. B. A mean reading rate of 90.8 wpm is not unusual since the probability of obtaining a result of 90.8 wpm or more is 0.1003. This means that we would expect a mean reading rate of 90.8 or higher from a population whose mean reading rate is 88 in 10 of every 100 random samples of size n = 21 students. The new program is not abundantly more effective than the old program. (f) There is a 5% chance that the mean reading speed of a random sample of 22 second grade students will exceed what value? There is a 5% chance that the mean reading speed of a random sample of 22 second grade students will exceed _____ wpm. (Round to two decimal places as needed.)
### Standard Normal Distribution Table (Page 1) #### Description The standard normal distribution table provides the area (probability) to the left of a given z-score in a standard normal distribution. #### Table Structure - **Graph**: A bell-shaped curve representing the normal distribution. The area under the curve to the left of a z-score (z) is shaded and labeled as "Area." - **Table**: Composed of two columns—the first column lists z-scores from -3.4 to -2.8 in increments of 0.1, while the second column gives the cumulative probability corresponding to each z-score. #### Values - **z = -3.4**: 0.0003 - **z = -3.3**: 0.0005 - **z = -3.2**: 0.0007 - **z = -3.1**: 0.0010 - **z = -3.0**: 0.0013 - **z = -2.9**: 0.0019 - **z = -2.8**: 0.0026 For each z-score, there are additional values in the table corresponding to the hundredths place (e.g., 0.00, 0.01, ..., 0.09). --- ### Standard Normal Distribution Table (Page 2) #### Description Continuing from Page 1, this table also shows the area to the left of a given z-score. #### Table Structure - **Graph**: Similar to Page 1, depicting the standard normal distribution. The area to the left of a z-score is shown as shaded. - **Table**: Composed of two columns—the first column ranges from z = 0.0 to z = 0.6 in increments of 0.1. Each row has probabilities for z-scores with different hundredths places. #### Values - **z = 0.0**: 0.5000 - **z = 0.1**: 0.5398 - **z = 0.2**: 0.5793 - **z = 0.3**: 0.6179 - **z = 0.4**: 0.6554 - **z = 0.5**: 0.691
Transcribed Image Text:### Standard Normal Distribution Table (Page 1) #### Description The standard normal distribution table provides the area (probability) to the left of a given z-score in a standard normal distribution. #### Table Structure - **Graph**: A bell-shaped curve representing the normal distribution. The area under the curve to the left of a z-score (z) is shaded and labeled as "Area." - **Table**: Composed of two columns—the first column lists z-scores from -3.4 to -2.8 in increments of 0.1, while the second column gives the cumulative probability corresponding to each z-score. #### Values - **z = -3.4**: 0.0003 - **z = -3.3**: 0.0005 - **z = -3.2**: 0.0007 - **z = -3.1**: 0.0010 - **z = -3.0**: 0.0013 - **z = -2.9**: 0.0019 - **z = -2.8**: 0.0026 For each z-score, there are additional values in the table corresponding to the hundredths place (e.g., 0.00, 0.01, ..., 0.09). --- ### Standard Normal Distribution Table (Page 2) #### Description Continuing from Page 1, this table also shows the area to the left of a given z-score. #### Table Structure - **Graph**: Similar to Page 1, depicting the standard normal distribution. The area to the left of a z-score is shown as shaded. - **Table**: Composed of two columns—the first column ranges from z = 0.0 to z = 0.6 in increments of 0.1. Each row has probabilities for z-scores with different hundredths places. #### Values - **z = 0.0**: 0.5000 - **z = 0.1**: 0.5398 - **z = 0.2**: 0.5793 - **z = 0.3**: 0.6179 - **z = 0.4**: 0.6554 - **z = 0.5**: 0.691
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