The reaction of 25.0 g benzene, C6H6, withexcess HNO3 resulted in 21.4 g C6H5NO2. Whatis the percentage yield?C6H6 + HNO3 → C6H5NO2 + H2Oa) 100%b) 27.4%c)54.3%d) 85.6%

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Answered: The reaction of 25.0 g benzene, C6H6,…

Chemistry for Engineering Students

4th Edition

ISBN:9781337398909

Author:Lawrence S. Brown, Tom Holme

Publisher:Lawrence S. Brown, Tom Holme

Chapter4: Stoichiometry

Section: Chapter Questions

Problem 4.45PAE: 4.45 If 21 g of H2S is mixed with 38 g of O2 and 31 g of SO2 forms, what is the percentage yield?...

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Similar questions

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The reaction of methane and water is one way to prepare hydrogen for use as a fuel: CH4(g) + H2O(g) CO(g) + 3 H2(g) If this reaction has a 37% yield under certain conditions, what mass of CH4 is required to produce 15 g of H2?
4.45 If 21 g of H2S is mixed with 38 g of O2 and 31 g of SO2 forms, what is the percentage yield? 2H2S+3O22SO2+2H2O
Hexamethylenediamine (C6H16N2) is one of the starting materials for the production of nylon. It can be prepared from adipic acid (C6H10O4) by the following overall equation: C6H10O4(l) + 2NH3(g) + 4H2(g) C6H16N2 (l) + 4H2O (l) What is the percent yield for the reaction if 765 g of hexamethylenediamine is made from 1.00 103 g of adipic acid?
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4.108 Elemental analysis is sometimes carried out by combustion of the sample. For a hydrocarbon, the only products formed are CO2 and H2O. If a 1.36-g sample of an unknown hydrocarbon is burned and 2.21 g of H2O is produced along with 4.07 g of CO2, what is the empirical formula of the hydrocarbon?
4.43 Magnesium nitride forms in a side reaction when magnesium metal burns in air. This reaction may also be carried out in pure nitrogen. 3Mg(s)+N2(g)Mg3N2(s) If 18.4 g of Mg3N2forms from the reaction of 20.0 g of magnesium with excess nitrogen, what is the percentage yield?

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The reaction of 25.0 g benzene, C6H6, with excess HNO3 resulted in 21.4 g C6H5NO2. What is the percentage yield? C6H6 + HNO3 → C6H5NO2 + H2O a) 100% b) 27.4% c) 54.3% d) 85.6%