The reaction for producing glucose in plants, called photosynthesis, is light 6CO₂ + 6H₂0C6H₁2O6 +60₂ If a plant produces 6.66 mol C6H₁2O6, how many moles of H₂O are needed? moles H₂O: mol
The reaction for producing glucose in plants, called photosynthesis, is light 6CO₂ + 6H₂0C6H₁2O6 +60₂ If a plant produces 6.66 mol C6H₁2O6, how many moles of H₂O are needed? moles H₂O: mol
Chemistry
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ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
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## Photosynthesis and Glucose Production
**Question 1 of 9:**
The reaction for producing glucose in plants, called photosynthesis, is:
\[ 6 \mathrm{CO}_2 + 6 \mathrm{H}_2\mathrm{O} \xrightarrow{\text{light}} \mathrm{C}_6\mathrm{H}_{12}\mathrm{O}_6 + 6 \mathrm{O}_2 \]
If a plant produces 6.66 mol of \(\mathrm{C}_6\mathrm{H}_{12}\mathrm{O}_6\), how many moles of \(\mathrm{H}_2\mathrm{O}\) are needed?
\[ \text{moles } \mathrm{H}_2\mathrm{O}: \, \underline{\hspace{3cm}} \text{mol} \]
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**Explanation:**
This reaction represents the process of photosynthesis, where six molecules of carbon dioxide (\(\mathrm{CO}_2\)) and six molecules of water (\(\mathrm{H}_2\mathrm{O}\)) react in the presence of light to form one molecule of glucose (\(\mathrm{C}_6\mathrm{H}_{12}\mathrm{O}_6\)) and six molecules of oxygen (\(\mathrm{O}_2\)). The question asks for the calculation of the number of moles of water needed if the plant produces 6.66 moles of glucose.
**Hint:**
Use the stoichiometric coefficients from the reaction to determine the proportional relationship between the number of moles of \(\mathrm{H}_2\mathrm{O}\) and \(\mathrm{C}_6\mathrm{H}_{12}\mathrm{O}_6\). Since the ratio of \(\mathrm{H}_2\mathrm{O}\) to \(\mathrm{C}_6\mathrm{H}_{12}\mathrm{O}_6\) in the balanced equation is 6:1, multiply 6.66 moles of \(\mathrm{C}_6\mathrm{H}_{12}\mathrm{O}_6\) by 6 to find the moles of \(\mathrm{H}_2\mathrm{O}\) needed.
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Transcribed Image Text:---
## Photosynthesis and Glucose Production
**Question 1 of 9:**
The reaction for producing glucose in plants, called photosynthesis, is:
\[ 6 \mathrm{CO}_2 + 6 \mathrm{H}_2\mathrm{O} \xrightarrow{\text{light}} \mathrm{C}_6\mathrm{H}_{12}\mathrm{O}_6 + 6 \mathrm{O}_2 \]
If a plant produces 6.66 mol of \(\mathrm{C}_6\mathrm{H}_{12}\mathrm{O}_6\), how many moles of \(\mathrm{H}_2\mathrm{O}\) are needed?
\[ \text{moles } \mathrm{H}_2\mathrm{O}: \, \underline{\hspace{3cm}} \text{mol} \]
---
**Explanation:**
This reaction represents the process of photosynthesis, where six molecules of carbon dioxide (\(\mathrm{CO}_2\)) and six molecules of water (\(\mathrm{H}_2\mathrm{O}\)) react in the presence of light to form one molecule of glucose (\(\mathrm{C}_6\mathrm{H}_{12}\mathrm{O}_6\)) and six molecules of oxygen (\(\mathrm{O}_2\)). The question asks for the calculation of the number of moles of water needed if the plant produces 6.66 moles of glucose.
**Hint:**
Use the stoichiometric coefficients from the reaction to determine the proportional relationship between the number of moles of \(\mathrm{H}_2\mathrm{O}\) and \(\mathrm{C}_6\mathrm{H}_{12}\mathrm{O}_6\). Since the ratio of \(\mathrm{H}_2\mathrm{O}\) to \(\mathrm{C}_6\mathrm{H}_{12}\mathrm{O}_6\) in the balanced equation is 6:1, multiply 6.66 moles of \(\mathrm{C}_6\mathrm{H}_{12}\mathrm{O}_6\) by 6 to find the moles of \(\mathrm{H}_2\mathrm{O}\) needed.
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