The reaction A+B ↔ C is carried out adiabatically in a constant-volume batch reactor. The rate law is –rA=k1CA1/2 CB1/2 – k2CC. Plot the conversion, temperature and concentration of the reacting species as a function of time. Entering Temperature: 2000Ck1 (373K) = 2.5 x 10-3 s-1 E1 = 98 kJ/molk2 (373K) = 3.8 x 10-5 s-1 E2 = 145 kJ/molCA0 = 0.05 mol/dm3 CPA = 25 J/mol/KCB0 = 0.10 mol/dm3 CPB = 35 J/mol/KΔH0Rx (298 K) = -45,000 J/mol A CPC = 47 J/mol/K
The reaction A+B ↔ C is carried out adiabatically in a constant-volume batch reactor. The rate law is –rA=k1CA1/2 CB1/2 – k2CC. Plot the conversion, temperature and concentration of the reacting species as a function of time. Entering Temperature: 2000Ck1 (373K) = 2.5 x 10-3 s-1 E1 = 98 kJ/molk2 (373K) = 3.8 x 10-5 s-1 E2 = 145 kJ/molCA0 = 0.05 mol/dm3 CPA = 25 J/mol/KCB0 = 0.10 mol/dm3 CPB = 35 J/mol/KΔH0Rx (298 K) = -45,000 J/mol A CPC = 47 J/mol/K
Introduction to Chemical Engineering Thermodynamics
8th Edition
ISBN:9781259696527
Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Publisher:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Chapter1: Introduction
Section: Chapter Questions
Problem 1.1P
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The reaction A+B ↔ C is carried out adiabatically in a constant-volume batch reactor. The rate law is –rA=k1CA1/2 CB1/2 – k2CC. Plot the conversion, temperature and concentration of the reacting species as a function of time.
Entering Temperature: 2000C
k1 (373K) = 2.5 x 10-3 s-1 E1 = 98 kJ/mol
k2 (373K) = 3.8 x 10-5 s-1 E2 = 145 kJ/mol
CA0 = 0.05 mol/dm3 CPA = 25 J/mol/K
CB0 = 0.10 mol/dm3 CPB = 35 J/mol/K
ΔH0Rx (298 K) = -45,000 J/mol A CPC = 47 J/mol/K
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