The reaction 2 NO(9) + Cl2 (9) -- 2 NOCI(9) was studied at –10°C, The following results were obtained, where d[Cl2] Rate = dt Initial Rate [NO], (mol/L) [(Cl], (mol/L) (mol L min) 0.13 0.12 0.36 0.13 0.24 0.73 0.26 0,24 2.90 (a) What is the rate law? (Use k for the rate constant.) Rate (b) What is the value of the rate constant? Rate constant= L mol min
The reaction 2 NO(9) + Cl2 (9) -- 2 NOCI(9) was studied at –10°C, The following results were obtained, where d[Cl2] Rate = dt Initial Rate [NO], (mol/L) [(Cl], (mol/L) (mol L min) 0.13 0.12 0.36 0.13 0.24 0.73 0.26 0,24 2.90 (a) What is the rate law? (Use k for the rate constant.) Rate (b) What is the value of the rate constant? Rate constant= L mol min
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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![The reaction
2 NO(9) + Cl2 (9) -→ 2 NOC(9)
was studied at -10°C. The following results were obtained, where
d[Cl2]
Rate =
dt
Initial Rate
[NO, (mol /L) [CL], (mol/L) (mol L min
")
0.13
0.12
0.36
0.13
0.24
0.73
0.26
0.24
2.90
(a) What is the rate law?
(Use k for the rate constant.)
Rate
(b) What is the value of the rate constant?
L mol 2 min
Rate constant=](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F4e5cc260-3b77-49e2-bff3-6598ee8567b8%2F1a116a72-f334-4a4f-95ba-af8720de0538%2Fwbfyfqxc_processed.jpeg&w=3840&q=75)
Transcribed Image Text:The reaction
2 NO(9) + Cl2 (9) -→ 2 NOC(9)
was studied at -10°C. The following results were obtained, where
d[Cl2]
Rate =
dt
Initial Rate
[NO, (mol /L) [CL], (mol/L) (mol L min
")
0.13
0.12
0.36
0.13
0.24
0.73
0.26
0.24
2.90
(a) What is the rate law?
(Use k for the rate constant.)
Rate
(b) What is the value of the rate constant?
L mol 2 min
Rate constant=
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