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The RC-circuit below can be modeled as sin100t V( R=50 C= 0.1 F di i dt C = E'(t) R- +-= Given E(t)=sin100t, R=5 ohms, C=0.1 F and i=0 when t=0. Solve the differential equation for 0st<0.05 with At=0.01. If the 500 10 exact solution is i=- 2501 10 -sin 100t – 2501 -cos 100t + -21 find the 2501 absolute errors at each iteration.

The RC-circuit below can be modeled as sin100t V( R=50 C= 0.1 F di i dt C = E'(t) R- +-= Given E(t)=sin100t, R=5 ohms, C=0.1 F and i=0 when t=0. Solve the differential equation for 0st<0.05 with At=0.01. If the 500 10 exact solution is i=- 2501 10 -sin 100t – 2501 -cos 100t + -21 find the 2501 absolute errors at each iteration.

Advanced Engineering Mathematics
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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The RC-circuit below can be modeled as sin100t V R=52 C= 0.1 F di i +- R- dt C = E '(t)| Given E(t) = sin100t, R=5 ohms, C=0.1 F and i=0 when t= 0. Solve the differential equation for 0st<0.05 with At = 0.01. If the 10 cos 100t + 500 10 e", find the 2501 -21 exact solution is i=- sin 100 - 2501 2501 absolute errors at each iteration.
Transcribed Image Text:The RC-circuit below can be modeled as sin100t V R=52 C= 0.1 F di i +- R- dt C = E '(t)| Given E(t) = sin100t, R=5 ohms, C=0.1 F and i=0 when t= 0. Solve the differential equation for 0st<0.05 with At = 0.01. If the 10 cos 100t + 500 10 e", find the 2501 -21 exact solution is i=- sin 100 - 2501 2501 absolute errors at each iteration.
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