The raw water supply for a community contains 160 mg/L total particulate matter. It is to be treated by addition of 86 mg/L alum. Essentially all of the added alum precipitates by this reaction: Al2(SO4)3 · 14H2O ⇒Al(OH)3(s) + 3SO2−4 + 6H+ + 8H2O. For a total flow of 5500 m3/day, compute the daily alum requirement. Answer in units of kg/day. Determine the concentration of solids in the water following alum addition (i.e., the sum of the solids initially present and those formed during treatment). Answer in units of mg/L.
The raw water supply for a community contains 160 mg/L total particulate matter. It is to be treated by addition of 86 mg/L alum. Essentially all of the added alum precipitates by this reaction: Al2(SO4)3 · 14H2O ⇒Al(OH)3(s) + 3SO2−4 + 6H+ + 8H2O. For a total flow of 5500 m3/day, compute the daily alum requirement. Answer in units of kg/day. Determine the concentration of solids in the water following alum addition (i.e., the sum of the solids initially present and those formed during treatment). Answer in units of mg/L.
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
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The raw water supply for a community contains 160 mg/L total particulate matter. It is
to be treated by addition of 86 mg/L alum.
Essentially all of the added alum precipitates
by this reaction:
Al2(SO4)3 · 14H2O ⇒Al(OH)3(s) + 3SO2−4 + 6H+ + 8H2O. For a total flow of 5500 m3/day, compute the daily alum requirement. Answer in units of kg/day.
Determine the concentration of solids in the water following alum addition (i.e., the sum of the solids initially present and those formed during treatment). Answer in units of mg/L.
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