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The rate that a chemical reaction produces the molecule W after t seconds is 3t + 3 gms/sec. What is the differential equation involving the mass of W? A. m' (t) = 3t + 3 B. m" (t) = 3t + 3 C. m(t) = 3 +3t D. NONE OF THE ABOVE What is the general solution to this equation (Please use C as the constant of integration): General Solution: W = 3t^2/2+3t+C If there was 4 gms of W initially, how much is there after 10 seconds? Mass = 180

The rate that a chemical reaction produces the molecule W after t seconds is 3t + 3 gms/sec. What is the differential equation involving the mass of W? A. m' (t) = 3t + 3 B. m" (t) = 3t + 3 C. m(t) = 3 +3t D. NONE OF THE ABOVE What is the general solution to this equation (Please use C as the constant of integration): General Solution: W = 3t^2/2+3t+C If there was 4 gms of W initially, how much is there after 10 seconds? Mass = 180

Functions and Change: A Modeling Approach to College Algebra (MindTap Course List)
Functions and Change: A Modeling Approach to College Algebra (MindTap Course List)
6th Edition
ISBN:9781337111348
Author:Bruce Crauder, Benny Evans, Alan Noell
Publisher:Bruce Crauder, Benny Evans, Alan Noell
Chapter2: Graphical And Tabular Analysis
Section2.1: Tables And Trends
Problem 1TU: If a coffee filter is dropped, its velocity after t seconds is given by v(t)=4(10.0003t) feet per...
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The rate that a chemical reaction produces the molecule W after t seconds is 3t + 3 gms/sec. What is the differential equation involving the mass of W? A. m' (t) = 3t + 3 В. т" (() — 3t + 3 С. т(t) 3 3 + 3t D. NONE OF THE ABOVE What is the general solution to this equation (Please use C as the constant of integration): General Solution: W = 3t^2/2+3t+C If there was 4 gms of W initially, how much is there after 10 seconds? Mass = 180
Transcribed Image Text:The rate that a chemical reaction produces the molecule W after t seconds is 3t + 3 gms/sec. What is the differential equation involving the mass of W? A. m' (t) = 3t + 3 В. т" (() — 3t + 3 С. т(t) 3 3 + 3t D. NONE OF THE ABOVE What is the general solution to this equation (Please use C as the constant of integration): General Solution: W = 3t^2/2+3t+C If there was 4 gms of W initially, how much is there after 10 seconds? Mass = 180
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