The rate law for your reaction is Rate= k[NO2]?. The rate constant for this reaction is 2.5 x 103/M s. If you started out with 0.55M NO2 and you ran the reaction for 5 minutes, what would be the concentration of 4. NO2?
The rate law for your reaction is Rate= k[NO2]?. The rate constant for this reaction is 2.5 x 103/M s. If you started out with 0.55M NO2 and you ran the reaction for 5 minutes, what would be the concentration of 4. NO2?
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Question
![Write the average rate
lon for the follo ing reaction.
b) If
sumption of H3P 4 is M/s, wh is the rate consumption of I' ?
What is the average r
or this ction?
3.
caction that is run at ^
constant of 2.52 x 10-5.
ame
Teactio
un at 157 r
ias a rate con
x 10-/s. Whe
activati
nergy for this
reacti
14 J/mol K)
o
0898mols
sec
4.
The rate law for your reaction is Rate= k[NO2]². The rate constant for this reaction is 2.5 x 10-3/M s. If
you started out with 0.55M NO2 and you ran the reaction for 5 minutes, what would be the concentration of
NO2?
13](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Ff35f8f89-65fc-4b90-98e9-68f8eaa1b3da%2F97d0c99a-8513-403e-9645-117a4cc44376%2Fvhn139_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Write the average rate
lon for the follo ing reaction.
b) If
sumption of H3P 4 is M/s, wh is the rate consumption of I' ?
What is the average r
or this ction?
3.
caction that is run at ^
constant of 2.52 x 10-5.
ame
Teactio
un at 157 r
ias a rate con
x 10-/s. Whe
activati
nergy for this
reacti
14 J/mol K)
o
0898mols
sec
4.
The rate law for your reaction is Rate= k[NO2]². The rate constant for this reaction is 2.5 x 10-3/M s. If
you started out with 0.55M NO2 and you ran the reaction for 5 minutes, what would be the concentration of
NO2?
13
Expert Solution
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Step 1
4)
Given,
Rate law for the reaction,
Rate = k[NO2]2
From rate law we can say that this is a second order reaction.
Initial concentration of NO2 = 0.55 M
Concentration of NO2 after 5 min = ?
Time (t) = 5 min = (5×60) s = 300 s
Rate constant (k) = 2.5 × 10-3/M s
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