The rate constant for the first-order decomposition of N20 is 3.40 s1. What is the half-life of the decomposition? O 0.424 s O 0.204 s O 0.491 s O 0.236 s O 0.294 s

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**Determining Half-Life for a First-Order Decomposition Reaction**

The rate constant for the first-order decomposition of N₂O is 3.40 s⁻¹. What is the half-life of the decomposition?

**Multiple Choice Options:**

- O 0.424 s
- O 0.204 s
- O 0.491 s
- O 0.236 s
- O 0.294 s

To solve this, you can use the formula for the half-life of a first-order reaction:

\[ t_{1/2} = \frac{0.693}{k} \]

where \( t_{1/2} \) is the half-life and \( k \) is the rate constant.

By substituting \( k = 3.40 s^{-1} \):

\[ t_{1/2} = \frac{0.693}{3.40} \approx 0.204 s \]

So, the half-life of the decomposition is approximately 0.204 seconds.

---

For educational purposes, it's important to understand the calculation of half-life from rate constants, especially in first-order reactions, as this knowledge is widely applicable in fields such as chemistry and pharmacokinetics.
Transcribed Image Text:**Determining Half-Life for a First-Order Decomposition Reaction** The rate constant for the first-order decomposition of N₂O is 3.40 s⁻¹. What is the half-life of the decomposition? **Multiple Choice Options:** - O 0.424 s - O 0.204 s - O 0.491 s - O 0.236 s - O 0.294 s To solve this, you can use the formula for the half-life of a first-order reaction: \[ t_{1/2} = \frac{0.693}{k} \] where \( t_{1/2} \) is the half-life and \( k \) is the rate constant. By substituting \( k = 3.40 s^{-1} \): \[ t_{1/2} = \frac{0.693}{3.40} \approx 0.204 s \] So, the half-life of the decomposition is approximately 0.204 seconds. --- For educational purposes, it's important to understand the calculation of half-life from rate constants, especially in first-order reactions, as this knowledge is widely applicable in fields such as chemistry and pharmacokinetics.
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