The rate at which a virus spreads through a population (measured in people per day) is given by the function r(t) = 2.33e1.165t, where t is the number of days since the initial infection. How many people were infected between days 7 and 14? Round your answer to the nearest person.

Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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**Educational Website Content**

**Title:** Calculation of Virus Spread Over Time

**Description:**
Understanding how a virus spreads through a population is crucial for controlling outbreaks. In mathematical terms, the rate at which a virus spreads can be represented by a specific function. Below, we explore a function that describes this rate and calculate the number of people infected over a given time period.

**Mathematical Model:**
The rate at which a virus spreads through a population (measured in people per day) is given by the function:

\[ r(t) = 2.33e^{1.165t} \]

where:
- \( r(t) \) is the rate of infection (people per day)
- \( t \) is the number of days since the initial infection

**Problem Statement:**
Calculate the number of people infected between days 7 and 14. Round your answer to the nearest person.

**Detailed Explanation:**
To find out how many people were infected between days 7 and 14, we need to integrate the given function \( r(t) \) from \( t = 7 \) to \( t = 14 \).

**Steps:**
1. Set up the integral to represent the total number of infections between days 7 and 14:

\[ \int_{7}^{14} 2.33e^{1.165t} \, dt \]

2. Solve the integral analytically:

\[ \int 2.33e^{1.165t} \, dt = \frac{2.33}{1.165} e^{1.165t} + C \]
\[ = 2.00 e^{1.165t} + C \]

3. Evaluate the integral from \( t = 7 \) to \( t = 14 \):

\[ \left[ 2.00 e^{1.165t} \right]_{7}^{14} = 2.00 e^{1.165 \cdot 14} - 2.00 e^{1.165 \cdot 7} \]

4. Calculate the exponential values and subtract:

\[ 2.00 e^{1.165 \cdot 14} - 2.00 e^{1.165 \cdot 7} \approx 2.00 (1235072.36) - 2.00 (518.02) \]
\[ \approx 2470144
Transcribed Image Text:**Educational Website Content** **Title:** Calculation of Virus Spread Over Time **Description:** Understanding how a virus spreads through a population is crucial for controlling outbreaks. In mathematical terms, the rate at which a virus spreads can be represented by a specific function. Below, we explore a function that describes this rate and calculate the number of people infected over a given time period. **Mathematical Model:** The rate at which a virus spreads through a population (measured in people per day) is given by the function: \[ r(t) = 2.33e^{1.165t} \] where: - \( r(t) \) is the rate of infection (people per day) - \( t \) is the number of days since the initial infection **Problem Statement:** Calculate the number of people infected between days 7 and 14. Round your answer to the nearest person. **Detailed Explanation:** To find out how many people were infected between days 7 and 14, we need to integrate the given function \( r(t) \) from \( t = 7 \) to \( t = 14 \). **Steps:** 1. Set up the integral to represent the total number of infections between days 7 and 14: \[ \int_{7}^{14} 2.33e^{1.165t} \, dt \] 2. Solve the integral analytically: \[ \int 2.33e^{1.165t} \, dt = \frac{2.33}{1.165} e^{1.165t} + C \] \[ = 2.00 e^{1.165t} + C \] 3. Evaluate the integral from \( t = 7 \) to \( t = 14 \): \[ \left[ 2.00 e^{1.165t} \right]_{7}^{14} = 2.00 e^{1.165 \cdot 14} - 2.00 e^{1.165 \cdot 7} \] 4. Calculate the exponential values and subtract: \[ 2.00 e^{1.165 \cdot 14} - 2.00 e^{1.165 \cdot 7} \approx 2.00 (1235072.36) - 2.00 (518.02) \] \[ \approx 2470144
**How much work does it take this squirrel to suck all the beer out of one of these cylindrical cans?** 

*Note: The straw reaches 3 in out of the can, the can is 4.5 in tall with a diameter of 2.5 in. This beer weighs 0.036 lb/in³.*
Transcribed Image Text:**How much work does it take this squirrel to suck all the beer out of one of these cylindrical cans?** *Note: The straw reaches 3 in out of the can, the can is 4.5 in tall with a diameter of 2.5 in. This beer weighs 0.036 lb/in³.*
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