The rate at which a body cools also depends on its exposed surface area S. If S is a constant, then a modification of (2), given in Section 3.1, is -ks(T-T). where k < 0 and T is a constant. Suppose that two cups A and B are filled with coffee at the same time. Initially, the temperature of the coffee is 160° F. The exposed surface area of the coffee in cup B is twice the surface area of the coffee in cup A. After 30 min the temperature of the coffee in cup A is 110° F. If T-80° F, then what is the temperature of the coffee in cup B after 30 min? (Round your answer to two decimal places.) °F

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The rate at which a body cools also depends on its exposed surface area S. If S is a constant, then a modification of (2), given in Section 3.1, is
. = KS(T - Tm),
where k < 0 and T is a constant. Suppose that two cups A and B are filled with coffee at the same time. Initially, the temperature of the coffee is 160° F. The exposed surface area of the coffee in cup B is twice the surface area of the coffee in cup A. After 30 min the temperature of the
coffee in cup A is 110° F. If Tm = 80° F, then what is the temperature of the coffee in cup B after 30 min? (Round your answer to two decimal places.)
OF
Transcribed Image Text:The rate at which a body cools also depends on its exposed surface area S. If S is a constant, then a modification of (2), given in Section 3.1, is . = KS(T - Tm), where k < 0 and T is a constant. Suppose that two cups A and B are filled with coffee at the same time. Initially, the temperature of the coffee is 160° F. The exposed surface area of the coffee in cup B is twice the surface area of the coffee in cup A. After 30 min the temperature of the coffee in cup A is 110° F. If Tm = 80° F, then what is the temperature of the coffee in cup B after 30 min? (Round your answer to two decimal places.) OF
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