The rate at which a body cools also depends on its exposed surface area S. If S is a constant, then a modification of (2), given in Section 3.1, is dT = KS(T-Tm). dt where k < 0 and T is a constant. Suppose that two cups A and B are filled with coffee at the same time. Initially, the temperature of the coffee is 165° F. The exposed surface area of the coffee in cup B is twice the surface area of the coffee in cup A. After 30 min the temperature of the coffee in cup A is 115° F. If Tm = 85° F, then what is the temperature of the coffee in cup B after 30 min? (Round your answer to two decimal places.) °F
The rate at which a body cools also depends on its exposed surface area S. If S is a constant, then a modification of (2), given in Section 3.1, is dT = KS(T-Tm). dt where k < 0 and T is a constant. Suppose that two cups A and B are filled with coffee at the same time. Initially, the temperature of the coffee is 165° F. The exposed surface area of the coffee in cup B is twice the surface area of the coffee in cup A. After 30 min the temperature of the coffee in cup A is 115° F. If Tm = 85° F, then what is the temperature of the coffee in cup B after 30 min? (Round your answer to two decimal places.) °F
Chapter3: Polynomial Functions
Section3.5: Mathematical Modeling And Variation
Problem 7ECP: The kinetic energy E of an object varies jointly with the object’s mass m and the square of the...
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Transcribed Image Text:The rate at which a body cools also depends on its exposed surface area S. If S is a constant, then a modification of (2), given
in Section 3.1, is
dT
= KS(T-Tm).
dt
where k < 0 and Tm is a constant. Suppose that two cups A and B are filled with coffee at the same time. Initially, the
temperature of the coffee is 165° F. The exposed surface area of the coffee in cup B is twice the surface area of the coffee in
cup A. After 30 min the temperature of the coffee in cup A is 115° F. If Tm = 85° F, then what is the temperature of the coffee
in cup B after 30 min? (Round your answer to two decimal places.)
OF
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