The random variable X has the density function: fox) = 52-x), 0sxs1 (a) The standard deviation of X is . (Round to four decimal places including any zeros.) (b) According to the Chebyshev's theorem, for k= 1.78, the probability P(O

A First Course in Probability (10th Edition)
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Chapter1: Combinatorial Analysis
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Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...
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The random variable X has the density function:
x) = (2-x). 0sxs1
f(x) =
(a) The standard deviation of X is |. (Round to four decimal places including any zeros.)
(b) According to the Chebyshev's theorem, for k= 1.78, the probability P O<X<D will be greater than or equal to
(Round to four decimal places including any zeros.)
(c) Since the actual value of this probability is , it can be said that the Chebyshev's theorem
V for k= 1.78.
(Round to four decimal places including any zeros.)
holds
does not hold
Transcribed Image Text:The random variable X has the density function: x) = (2-x). 0sxs1 f(x) = (a) The standard deviation of X is |. (Round to four decimal places including any zeros.) (b) According to the Chebyshev's theorem, for k= 1.78, the probability P O<X<D will be greater than or equal to (Round to four decimal places including any zeros.) (c) Since the actual value of this probability is , it can be said that the Chebyshev's theorem V for k= 1.78. (Round to four decimal places including any zeros.) holds does not hold
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