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The radius of the roll of paper shown in the figure (Figure 1) is 7.5 cm and its moment of inertia is I = 3.2x103 kg m² . A force of 2.4 N is exerted on the end of the roll for 1.5 s , but the paper does not tear so it begins to unroll. A constant friction torque of 0.13 m · N is exerted or the roll which gradually brings it to a stop.

The radius of the roll of paper shown in the figure (Figure 1) is 7.5 cm and its moment of inertia is I = 3.2x103 kg m² . A force of 2.4 N is exerted on the end of the roll for 1.5 s , but the paper does not tear so it begins to unroll. A constant friction torque of 0.13 m · N is exerted or the roll which gradually brings it to a stop.

College Physics
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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Can you provide me with the solution and the work for this problem that I cannot get for my physics midterm study guide? I have attached images of it below - there are two parts. Thanks!!

The radius of the roll of paper shown in the figure (Figure 1) is 7.5 cm, and its moment of inertia is \( I = 3.2 \times 10^{-3} \, \text{kg} \cdot \text{m}^2 \). A force of 2.4 N is exerted on the end of the roll for 1.5 s, but the paper does not tear as it begins to unroll. A constant friction torque of 0.13 m ∙ N is exerted on the roll, which gradually brings it to a stop. **Explanation of Figure:** The illustration depicts a roll of paper with an axis running horizontally through its center. The roll is shown starting to unroll, with a downward force \( \mathbf{F} \) applied at the edge of the paper. This force initiates the unrolling of the paper from the roll.
Transcribed Image Text:The radius of the roll of paper shown in the figure (Figure 1) is 7.5 cm, and its moment of inertia is \( I = 3.2 \times 10^{-3} \, \text{kg} \cdot \text{m}^2 \). A force of 2.4 N is exerted on the end of the roll for 1.5 s, but the paper does not tear as it begins to unroll. A constant friction torque of 0.13 m ∙ N is exerted on the roll, which gradually brings it to a stop. **Explanation of Figure:** The illustration depicts a roll of paper with an axis running horizontally through its center. The roll is shown starting to unroll, with a downward force \( \mathbf{F} \) applied at the edge of the paper. This force initiates the unrolling of the paper from the roll.
**Part A** Assuming that the paper's thickness is negligible, calculate the length of paper that unrolls during the time that the force is applied (1.5 s). *Express your answer using two significant figures.* \[ l = \text{\_\_\_\_\_\_\_\_\_} \text{ m} \] [Submit] [Request Answer] --- **Part B** Assuming that the paper's thickness is negligible, calculate the length of paper that unrolls from the time the force ends to the time when the roll has stopped moving. *Express your answer using two significant figures.* \[ l = \text{\_\_\_\_\_\_\_\_\_} \text{ m} \] [Submit] [Request Answer]
Transcribed Image Text:**Part A** Assuming that the paper's thickness is negligible, calculate the length of paper that unrolls during the time that the force is applied (1.5 s). *Express your answer using two significant figures.* \[ l = \text{\_\_\_\_\_\_\_\_\_} \text{ m} \] [Submit] [Request Answer] --- **Part B** Assuming that the paper's thickness is negligible, calculate the length of paper that unrolls from the time the force ends to the time when the roll has stopped moving. *Express your answer using two significant figures.* \[ l = \text{\_\_\_\_\_\_\_\_\_} \text{ m} \] [Submit] [Request Answer]
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