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The radius of a simple curve is half the length of the long chord, what is the angle of intersection? 30 degrees 35 degrees 45 degress 40 degrees

Traffic and Highway Engineering

5th Edition

ISBN:9781305156241

Author:Garber, Nicholas J.

Publisher:Garber, Nicholas J.

Chapter15: Geometric Design Of Highway Facilities

Section: Chapter Questions

Problem 7P

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Question

The radius of a simple curve is half the length of the long chord, what is the
angle of intersection?
30 degrees
35 degrees
45 degress
40 degrees

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On a railroad line, two tangents that intersect at station 10 + 243 so as to form an angle of 36°28′ are to be connected by a compound curve consisting of two simple curves. The simple curve beginning at the P.C. which is at station 10 + 163 is to be a 4° curve whose degree is based on a 20m chord and is to have a central angle of 17°. Using chord basis, a. What should be the radius of the other simple curve that ends at the P.T.?b. Compute the stationing of P.C.C.c. What is the length of the tangent from the P.I. to the P.T. of the compound curve?
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. A curve with radius (R) of 700.00 feet and a central angle (I) of 450 00’ 00” has a PC station of 10+00.00. The equation station at the PT is: A. 16+35.30 back = 16+70.94 ahead B. 16+28.32 back = 16+62.74 ahead C. 16+14.18 back = 15+86.43 ahead D. 15+97.34 back = 15+86.43 ahead
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On a railroad line, two tangents that intersect at station 10+243 so as to form an angle of 36028' are to be connected by a compound curve consisting of two simple curves. The BC which is at station 10 + 163 is to be a 40 curve based on a 20 m chord and is to have a central angle of 170. Compute R2, the stationing of PCC, and the length of tangent from Pl to EC. 10 + 243 PI 36°28' V1. ti t2 V2 PCC EC 10 + 163 BC R2 R1