The question is the following: 1st A metal , "M", was converted to the phosphate M3(PO4)2. 2nd Then a solution of the above phosphate was treated with Barium chloride to give Barium phosphate crystals (the result of a "Double Replacement" reaction), which were filtered off. Problem: If 11.6 g of the above metal (from the first part of this question) gave 24.378 grams of Barium phosphate (in the second part of this problem), what is the atomic weight of the metal? Which element is this metal?
The question is the following:
1st A metal , "M", was converted to the phosphate M3(PO4)2.
2nd Then a solution of the above phosphate was treated with Barium chloride to give Barium phosphate crystals (the result of a "Double Replacement" reaction), which were filtered off.
Problem: If 11.6 g of the above metal (from the first part of this question) gave 24.378 grams of Barium phosphate (in the second part of this problem), what is the atomic weight of the metal? Which element is this metal?
I've found the chemical formula, blanced the equation and set up a chart of theory moles, actual moles and grams. I have found the chart masses for BaCl2 and Ba3(PO4)2, I've found the actual moles of both those compounds as well. I don't know how to find out what M is.
Answer:
This question is based on law of constant proportion which states that in a compound all its constituent elements are always present in the fixed ratio by mass.
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