The purpose of this function is to return the index i of the segment [xi, Xi+1] that contains x. Its input arguments are: int n: the size of the grid (number of grid points) double *xi: the array of size n containing the grid coordinates double x: the coordinate of the point that we want to locate There are 4 mistakes (bugs) in this function. Find them and fix them! Answer: (penalty regime: 10, 20, ... %) Reset answer 1 2 3 4- 5 6 7 8 9 10 11 68694AWNE 14 15 16 17 18 19 20 E221222222222222223333 Given an array of coordinates xi for an * ordered uniform grid of size n and a * value x, locate the index i for which x \in [xi[i], xi [i+1]). (We assume that *the grid is given in incremental order * * i.e. xi[i+1] - xi[i] > 0) * int locate(int n, double *xi, double x) { int idx; double a, b, dx; /* assign edge values of interpolation interval */ a = xi [0] b = xi[n-1]; /* Calculate step size */ dx = (b-a)/(n); /* Special treatment if x-b */ if (x b) return n-1; /* Check that x \in [a,b] */ if (x b) { 23 24 25 26 } 27 28 29 30 32} printf("ERROR: Point lies outside the grid.\n"); return -1; Find index assuming uniform grid */ idx round((x-a)/dx); return idx;
The purpose of this function is to return the index i of the segment [xi, Xi+1] that contains x. Its input arguments are: int n: the size of the grid (number of grid points) double *xi: the array of size n containing the grid coordinates double x: the coordinate of the point that we want to locate There are 4 mistakes (bugs) in this function. Find them and fix them! Answer: (penalty regime: 10, 20, ... %) Reset answer 1 2 3 4- 5 6 7 8 9 10 11 68694AWNE 14 15 16 17 18 19 20 E221222222222222223333 Given an array of coordinates xi for an * ordered uniform grid of size n and a * value x, locate the index i for which x \in [xi[i], xi [i+1]). (We assume that *the grid is given in incremental order * * i.e. xi[i+1] - xi[i] > 0) * int locate(int n, double *xi, double x) { int idx; double a, b, dx; /* assign edge values of interpolation interval */ a = xi [0] b = xi[n-1]; /* Calculate step size */ dx = (b-a)/(n); /* Special treatment if x-b */ if (x b) return n-1; /* Check that x \in [a,b] */ if (x b) { 23 24 25 26 } 27 28 29 30 32} printf("ERROR: Point lies outside the grid.\n"); return -1; Find index assuming uniform grid */ idx round((x-a)/dx); return idx;
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
Related questions
Question
Using C++
![The purpose of this function is to return the index i of the segment
[xi, Xi+1]
that contains x.
Its input arguments are:
int n: the size of the grid (number of grid points)
double *xi: the array of size n containing the grid coordinates
double x: the coordinate of the point that we want to locate
There are 4 mistakes (bugs) in this function. Find them and fix them!
Answer: (penalty regime: 10, 20, ... %)
Reset answer
1
2
3
4-
5
6
7
8
9
10
11
68694AWNE
14
15
16
17
18
19
20
E221222222222222223333
Given an array of coordinates xi for an
* ordered uniform grid of size n and a
* value x, locate the index i for which
x \in [xi[i], xi [i+1]). (We assume that
*the grid is given in incremental order
*
* i.e. xi[i+1] - xi[i] > 0) *
int locate(int n, double *xi, double x) {
int idx;
double a, b, dx;
/* assign edge values of interpolation interval */
a = xi [0]
b = xi[n-1];
/* Calculate step size */
dx = (b-a)/(n);
/* Special treatment if x-b */
if (x b) return n-1;
/* Check that x \in [a,b] */
if (x <a && x > b) {
23
24
25
26
}
27
28
29
30
32}
printf("ERROR: Point lies outside the grid.\n");
return -1;
Find index assuming uniform grid */
idx round((x-a)/dx);
return idx;](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F5704136c-277b-4154-88f1-e18dbecfa29c%2F3931414a-6dcd-4c86-a1b1-a294b59d216d%2F0xhgghv_processed.jpeg&w=3840&q=75)
Transcribed Image Text:The purpose of this function is to return the index i of the segment
[xi, Xi+1]
that contains x.
Its input arguments are:
int n: the size of the grid (number of grid points)
double *xi: the array of size n containing the grid coordinates
double x: the coordinate of the point that we want to locate
There are 4 mistakes (bugs) in this function. Find them and fix them!
Answer: (penalty regime: 10, 20, ... %)
Reset answer
1
2
3
4-
5
6
7
8
9
10
11
68694AWNE
14
15
16
17
18
19
20
E221222222222222223333
Given an array of coordinates xi for an
* ordered uniform grid of size n and a
* value x, locate the index i for which
x \in [xi[i], xi [i+1]). (We assume that
*the grid is given in incremental order
*
* i.e. xi[i+1] - xi[i] > 0) *
int locate(int n, double *xi, double x) {
int idx;
double a, b, dx;
/* assign edge values of interpolation interval */
a = xi [0]
b = xi[n-1];
/* Calculate step size */
dx = (b-a)/(n);
/* Special treatment if x-b */
if (x b) return n-1;
/* Check that x \in [a,b] */
if (x <a && x > b) {
23
24
25
26
}
27
28
29
30
32}
printf("ERROR: Point lies outside the grid.\n");
return -1;
Find index assuming uniform grid */
idx round((x-a)/dx);
return idx;
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