The pulse rates of 166 randomly selected adult males vary from a low of 39 bpm to a high of 107 bpm. Find the minimum sample size required to estimate the mean pulse rate of adult males. Assume that we want 95% confidence that the sample mean is within 3 bpm of the population mean. Complete parts (a) through (c) below. a. Find the sample size using the range rule of thumb to estimate o. n = (Round up to the nearest whole number as needed.) b. Assume that o = 11.5 bpm, based on the value s = 11.5 bpm from the sample of 166 male pulse rates. n = (Round up to the nearest whole number as needed.) c. Compare the results from parts (a) and (b). Which result is likely to be better? The result from part (a) is the result from part (b). The result from is likely to be better because

Q: (47) 4+4

A:

Q: 0 1 2 4 0 0 1 3

A:

Q: a) : ?

A: here differentiate both sides with respect to x.

Q: 4 (2+ VT)5 5. Calculate 0.

A:

Q: 2x + 2y + z = 16 x + z = 34 y − 3z = 34

A:

Q: 1 tX

A: NOTE: Refresh your page if you can't see any equations. . ..............(1) substitute  take…

Q: (y>-- (2x-y 2-3 AALAM

A: Here we have to graph the given inequality:-  y>-x2-22x-y ≥-3

Q: -7 2. Fine the gcneral Selution

A: Given differential equation is: x2d2ydx2+xdydx+y=-7.     …..1 Substitute x=ez z=logx Now,…

Q: 2. Factor. 10 x2/5 (4x + 7)/2 +÷ 7 3 7/5 (4x + 7)-1/2 3

A:

Q: 8. Find YZ. 1 +1 19-31

A: Given: WXYZ is a parallelogram. And WX=11x+1YZ=19x-31

Q: 10.1-2 q 6

A: Image is attached with detailed solution.

Q: 4. I dr 2r + 1 r-1

A: NOTE: Refresh your page if you can't see any equations. . here we can write  1=-2+3

Q: 3 Q 4. Differentiate Vx2 Vx2 2 +

A: