The proportion \( p \) of residents in a community who recycle has traditionally been 60%. A policy maker claims that the proportion is less than 60% now that one of the recycling centers has been relocated. If 116 out of a random sample of 225 residents in the community said they recycle, is there enough evidence to support the policy maker's claim at the 0.01 level of significance?Perform a one-tailed test. Then complete the parts below.Carry your intermediate computations to three or more decimal places. (If necessary, consult a list of formulas.)(a) State the null hypothesis \( H_0 \) and the alternative hypothesis \( H_1 \).\[ H_0 : \]\[ H_1 : \](b) Determine the type of test statistic to use.\( \text{[Choose one]} \)(c) Find the value of the test statistic. (Round to three or more decimal places.)\[ \](d) Find the \( p \)-value. (Round to three or more decimal places.)\[ \](e) Is there enough evidence to support the policy maker's claim that the proportion of residents who recycle is less than 60%?\( \text{[Yes]} \) \( \text{[No]} \) The right side of the image contains symbols and notations for mathematical expressions commonly used in hypothesis testing.

Givenclaim is that the proportion of residents who recylce is less than 60%x=116sample…

Answered: The proportion p of residents in a…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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What do the results mean? What type of error could you be making and what would that mean? Redo as a one-tail test, expecting a decrease in the number of headaches. Pay attention to what changes and what doesn’t and why.
please do the following parts, this is one question! hypotheses, assumptions, and please check the assumptions (listed as a problem in the image)
According to a report on consumer fraud and identity theft, 22% of all complaints for a year were for identity theft. In that year, Wisconsin had 787 complaints of identity theft out of 3498 consumer complaints. Does this data provide enough evidence to show that Wisconsin had a higher proportion of identity theft than 22%? Test at the 1% level. State the hypotheses. Ho: p? v Ha: p|? v Calculate the test statistic. Round to four decimal places. Calculate the standardized test statistic. Round to three decimal places. Z = Find the p-value. Round to four decimal places. p-value = State your decision. O Since the p-value is less than .01, reject Họ. O Since the p-value is greater than .01, reject Ho. O Since the p-value is less than .01, fail to reject Ho. O Since the p-value is greater than .01, fail to reject Ho. Interpret the results. O At the 1% level of significance, there is enough evidence to show that the proportion of complaints due to identity theft in Wisconsin is not equal to…
One urban affairs sociologist claims that the proportion, p, of adult residents of a particular city who have been victimized by a criminal is at least 55%. A random sample of 160 adult residents of this city were questioned, and it was found that 71 of them had been victimized by a criminal. Based on these data, can we reject the sociologist's claim at the 0.05 level of significance? Perform a one-tailed test. Then complete the parts below. Carry your intermediate computations to three or more decimal places and round your answers as specified in the table. (If necessary, consult a list of formulas.) (a) State the null hypothesis H, and the alternative hypothesis H,. H. :0 H :0 (b) Determine the type of test statistic to use. (Choose one) ▼ O=0 OSO O20 (c) Find the value of the test statistic. (Round to three or more decimal places.) O
A cigarette manufacturer claims that his cigarettes have nicotine content that does not exceed 2.0 milligrams. If a random sample of 10 cigarettes of this type have nicotine contents of 2.0, 2.3 1.7, 2.2, 1.9, 2.2, 2.0, 2.5, 2.1 and 1.9 milligrams, would you agree with the manufacturer's claim? a = 0.05. What is the correct set of hypotheses to test this claim? (Α) H0: μ 2.0 Β) H0:μ2.0; H1: μ # 2.0 c) HO:µ > 2.0; H1: µ 2.0
option d. for the last question is D. The P-value is greater than the level of significance so there is not sufficient evidence to conclude the new system is effective.
When a researcher changes their data analyses to get the p-value they desire, that is known as a. HARKing b. p-hacking c. multiple comparisons d. a Type II error
According to a report on consumer fraud and identity theft, 20% of all complaints for a year were for identity theft. In that year, Rhode Island had 717 complaints of identity theft out of 3498 consumer complaints. Does this data provide enough evidence to show that Rhode Island had a higher proportion of identity theft than 20%? Test at the 5% level. State the hypotheses. Họ: p ? Ha: P Calculate the test statistic. Round to four decimal places. Calculate the standardized test statistic. Round to three decimal places. z = Find the p-value. Round to four decimal places. p-value = State your decision. O Since the p-value is less than .05, reject Ho. O Since the p-value is greater than .05, fail to reject Hg. O Since the p-value is less than .05, fail to reject Hg. O Since the p-value is greater than .05, reject Ho. Interpret the results. O At the 5% level of significance, there is enough evidence to show that the proportion of complaints due to identity theft in Rhode Island is more than…
Please look at the picture and provide full details answer
Please manually solve this not using excel. Thx
Several studies showed that after eating a low-fat cereal for two meals a day, subjects had lost some weight.A cereal companyfinanced this research. Identify what is wrong. Choose the correct answer below. A. Since the research is composed of voluntary response samples, there may be key data points missing. B. The data used in the studies is not reliable because it was not measured by the administrator. C. It is questionable that the sponsor is a cereal company because this sponsor can be greatly affected by the conclusion. D. It is not possible to take accurate measurements.
According to the USDA World Agricultural Supply and Demand Estimates report found that Americans consumed an average of 279 eggs per person in 2019. The farmers at Eggcellent Acres believes the number of eggs consumed by Americans has increased over the last few years. Based on the Minitab printout below, test to determine if the average number of eggs consumed by Americans has increased. Test at the 0.10 level of significance. (Show all six steps.) One-Sample T: Eggs Consumed Descriptive Statistics N Mean StRex SE Mean 78 285.00 22.59 2.56 i population mean of Sample Test Null hypothesis Ho: M = 279 Alternative hypothesis Hi: u > 279 T-Value P-Value 2.35 0.011 95% Lower Bound for y 280.74

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